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max2010maxim [7]
3 years ago
8

X^2-2x-15=0 x^2-7x=18 4n^2=4n+36=0

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

Answer: oh  this is hard

Step-by-step explanation: its b

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Solve the equation 4p+9+(-7p)+2=
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4p+9-7p+2=
group like terms
4p-7p+9+2
addd like terms
-3p+11
that is simplified form

6 0
3 years ago
Sam has a cheese spreader in the shape below.
IRINA_888 [86]

Answer:

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Step-by-step explanation:

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3 years ago
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Are the two terms on each tile like terms? Sort the tiles into the appropriate categories.
o-na [289]

Answer:

Like terms: -7y^2 and y^2, 0.5kt and -10kt, 6 and 9

Not like terms: -4p and p^2, 5x and 5, 3ad and 2bd

Step-by-step explanation:

Two or more terms are called like terms if they have same variables and powers.

-7y^2 and y^2 are like terms because they have same variable y with same power 2.

-4p and p^2 are not like terms because they have same variable y with different powers.

0.5kt and -10kt are like terms because they have same variables kt with same power 1.

6 and 9 are like terms because both are constant.

5x and 5 are not like terms because one have variable and other is constant.

3ad and 2bd are not like terms because they have different variables.

Like terms: -7y^2 and y^2, 0.5kt and -10kt, 6 and 9

Not like terms: -4p and p^2, 5x and 5, 3ad and 2bd

7 0
3 years ago
Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm. What is Rich's percent error in this c
Hitman42 [59]

Answer:

0.9%

Step-by-step explanation:

We have been given that Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm.

We will use percentage error formula to solve our given problem.

\text{Percentage error}=\frac{\text{Experimental value-Actual value }}{\text{Actual actual}}\times 100

\text{Percentage error}=\frac{80.7-80}{80}\times 100

\text{Percentage error}=\frac{0.7}{80}\times 100

\text{Percentage error}=0.00875\times 100

\text{Percentage error}=0.875\approx 0.9

Therefore, Rich's percent error in calculation is 0.9%.

5 0
4 years ago
Find the midpoint of segment AB given. A (-3, 2) and B (3, -2)
Tasya [4]

\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ A(-3,\ 2)\ \text{and}\ B(3,\ -2).\ \text{Substitute:}\\\\x=\dfrac{-3+3}{2}=\dfrac{0}{2}=0\\\\y=\dfrac{2+(-2)}{2}=\dfrac{0}{2}=0\\\\Answer:\ \boxed{(0,\ 0)}

8 0
3 years ago
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