The given polynomial has a degree of 4, the leading coefficient is 3, and the constant is 4.4.
<h3>What is a polynomial?</h3>
A polynomial is an algebraic expression with terms that are the combination of variables, coefficients, and constants.
- The highest power of the variable is said to be the degree of the polynomial.
- The coefficient of the highest power variable is said to be the leading coefficient.
<h3>Calculation:</h3>
The given polynomial is
g(x) = 13.2x³ + 3x⁴ - x - 4.4
The highest power of the variable x is 4. So, the degree of the variable is 4.
Then, the leading coefficient is 3.
The constant on the given polynomial is 4.4.
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Question: For the given polynomial, identify the degree, leading coefficient, and the constant value.
g(x) = 13.2x³ + 3x⁴ - x - 4.4
<em>Here we are required to determine the initial monthly fee charged by the electric company.</em>
The initial fee charged by the electric company is; C = $10
To solve this, we need to evaluate the slope and intercepts of the equation of the straight line graph of the relation.
y = mx + c.
- where m = slope of the relation.
- and c = <em>intercept = the initial fee charged by the electric company</em>.
- y = <em>Monthly charge at each time</em>.
To find the slope;
By substituting m into the equation y = mx + c, alongside a pair of values of usage and monthly charge, we can obtain the intercept, c (i.e the initial fee charged).
Therefore, m = 0.12 , y = 82 and X = 600;
we then have;
Therefore, the initial fee charged by the electric company is; C = $10.
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6.9 as a fraction or mixed number
6.9 = 6 9/10
This is also the same as 69/10
Answer:
52.5
Step-by-step explanation:
Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement
Now, m<B = 105°, since ABCD is a parallelogram, <B = <D
so, m<ADC = 105° so, m<ADE = 180°-105° = 75°
Now, m<EAD+m<AED+m<ADE = 180°
or, m<AED+m<AED+m<ADE = 180°
or, x+x+75°=180°
or, 2x=180+75°
or, 2x=105°
or, x=52.5°
Let x = number of months.
Let y = total number of fish in pond.
6% of 3,000 = 180 fish
We can use an equation to help us with this problem.
y = 3,000 + 180x - 400x. Combine like terms.
y = 3,000 - 220x. Plug 9 in for x.
y = 3,000 - 220(9). Solve for y
y = 1,020.
There are 1,020 fish in the pond after 9 months.
