Answer:
The height of the right circular cylinder is 4.55 inches ⇒ b
Step-by-step explanation:
The formula of the surface area of a right circular cylinder is
S.A = 2πrh + 2πr², where
∵ The surface area of a right circular cylinder is 300 square inches
∴ S.A = 300 in.²
∵ Its radius is 5 inches
∴ r = 5 in.
∵ π = 3.14
→ Substitute them in the rule above
∵ 300 = 2(3.14)(5)(h) + 2(3.14)(5)²
∴ 300 = 31.4h + 157
→ Subtract 157 from both sides
∵ 300 - 157 = 31.4h + 157 - 157
∴ 143 = 31.4h
→ Divide both sides by 31.4
∵ 4.554140127 = h
∴ 4.55 = h
∴ The height of the right circular cylinder is 4.55 inches
6/9 = 2/3 cm^2
good luck :))))
Answer:
Its 2 on the x axis
Step-by-step explanation:
Answer:
440
Step-by-step explanation:
Her we have two objects: 2 square.
1st has dimension 5x5x8
2nd has dimension 10x10x2
But we also have invisible prarts, the bottom of 1st is on the top od the 2nd. So we will remove something.
The formula for the surface of the square is
S=2B+M
Surface area of the first is
S1=2x5x5+4x8x5=50+160=210
Surface are of the 2nd is
S2=2x10x10+4x10x2=200+80=280
S=s1+s2-50=210+280-50=440
This -50 is are od one base from first square 5x5=25 whic we added in s1, but in real it is invisible.
The same area we added in s2. The top is 10x10-5x5 (invisible prat).
So we added two times 25, it is 50.
I think it’s D. (don’t quote me on it) good luck hopefully this is helpful !!! :)
