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Alexandra [31]
3 years ago
7

Simplify. Remove all perfect squares from inside the square root. 30b^5

Mathematics
2 answers:
Allisa [31]3 years ago
7 0

I am assuming that 30b⁵ is written under root since it is mention that remove all perfect squares from inside the square root.

\sf \:  \sqrt{30b ^{5} }

Rewrite the exponent as a sum where one of the addends is a multiple of the index

\sf \sqrt{30 {b}^{4 + 1} }

Use a ^{m + n}  =  {a}^{m}  \times  {a}^{n} To expand the expression

\sf  \sqrt{30b^{4} \times b ^{1}  }

Any expression raised to the power of 1 equals itself

\sf  \sqrt{30 {b}^{4}  \times b}

The root of a product is equal to the product of the roots of each factor

\sf \sqrt{b ^{4} }  \sqrt{30b}

Reduce the index of the radical and exponent with 2

\sf \:  {b}^{2}  \sqrt{30b}

Murljashka [212]3 years ago
4 0

Factor out  {b}^{4}

\sqrt{30( {b}^{4} b)}

Rewrite \:  {b}^{4} as  {b}^{2} {)}^{2}

\sqrt{30(( {b}^{2} {)}^{2} b)}

Reorder 30 and  {b}^{2}  {)}^{2}

Add parentheses

\sqrt{( {b}^{2}  {)}^{2}.(30b) }

Pull terms out from under the radical.

{b}^{2}  \sqrt{30b}

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