3 years ago

Two questions about equivalent fractions

2 answers:

8 0

First photo 12-4m and the other is 2.38y+6

svlad2 [7]3 years ago

7 0

Answer:

first photo Answer12-4m secend 2.3/8y+6

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Ksenya-84 [330]

$x^2\cos y-\sin(y+4x)+\ln(1+x)=0$

Differentiate both sides with respect to $x$ , treating $y$ as a function of $x$ :

$2x\cos y-x^2\sin y\dfrac{\mathrm dy}{\mathrm dx}-\cos(y+4x)\left(\dfrac{\mathrm dy}{\mathrm dx}+4\right)+\dfrac1{1+x}=0$

$2x\cos y-4\cos(y+4x)-\left(x^2\sin y+\cos(y+4x)\right)\dfrac{\mathrm dy}{\mathrm dx}+\dfrac1{1+x}=0$

$\left(x^2\sin y+\cos(y+4x)\right)\dfrac{\mathrm dy}{\mathrm dx}=2x\cos y-4\cos(y+4x)+\dfrac1{1+x}$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x\cos y-4\cos(y+4x)+\frac1{1+x}}{x^2\sin y+\cos(y+4x)}$

At the point (0, 0), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}(0,0)=\dfrac{0-4\cos0+1}{0+\cos0}=-3$

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4 years ago

kicyunya [14]

Answer:

Step-by-step explanation:

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sesenic [268]

Theoretically, the answer is infinity. however, in a non perfect universe such as our own, practically the answer would be around 17ft.

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jonny [76]

Answer: $5x^{2} y ^{4}$

Step-by-step explanation:

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