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1 year ago

What the y-intercept of (8,0) and (3,7)

Mathematics

1 answer:

Anettt [7]1 year ago

3 0

Answer:

$\sf \bf y - intercept = \dfrac{56}{5}$

Step-by-step explanation:

Y-intercept:

(8,0) ; x₁ = 8 & y₁ = 0

(3,7) ; x₂= 3 & y₂ = 7

First find the slope of the line.

$\sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}$

$\sf = \dfrac{7 - 0}{3 - 8}\\\\ =\dfrac{7}{-5}\\\\=\dfrac{-7}{5}$

slope y-intercept form of the line: y = mx + b

Substitute the slope and x and y in the above equation. We can choose anyone of the given points.

$0 = \dfrac{-7}{5}*8 + b\\\\0=\dfrac{-56}{5}+b\\\\\dfrac{56}{5}=b\\\\ \boxed{\bf b = \dfrac{56}{5}}$

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An angle whose measure is –302° is in standard position. In which quadrant does the terminal side of the angle fall?

juin [17]

Answer: Quadrant 1 (northeast quadrant)

=================================================

Explanation:

Add on 360 degrees to do a full rotation

-302+360 = 58

So angles -302 degrees and 58 degrees are pointing in the same direction. These angles are in quadrant 1, which is the northeast quadrant

Note: because the angles -302 and 58 point in the same direction, we consider these angles to be coterminal.

3 0

3 years ago

Determine f(-1) if the graph of f(x) is given below.

-BARSIC- [3]

Answer:

$f(-1) = -2$

Step-by-step explanation:

Given

The attached graph

Required

$f(-1)$

This is the point where

$x = -1$

On the attached graph;

$f(x) = -2$ when $x = -1$

Hence:

$f(-1) = -2$

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2 years ago

Solve the inequality.

shusha [124]

Answer:

(3/2)x - 2 < 7

(3/2)x < 9

3x < 18

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answer is b

5 0

3 years ago

What is the solution for a2 -b2

Sphinxa [80]

2(a-b)

this is the answers

4 0

2 years ago

Read 2 more answers

Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

3 years ago