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2 years ago

Identify the graph of the compound inequality (-2 <2x-6) (3x-125 10).

Mathematics

1 answer:

Shtirlitz [24]2 years ago

7 0

Choose the first one. The process is shown in the following picture.

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At a restaurant, your bill has a food total of $28.20. Find the amount of an 15% tip on the food total.

damaskus [11]

Just multiply by 0.15 to get the tip amount and add to your original number. This gives you 32.43

3 0

2 years ago

Read 2 more answers

How do you solve 8x-7= 3x 9?

gtnhenbr [62]

8x - 7 = 3x + 9
8x - 3x = 9 + 7
5x = 16
x = 16/5 = 3 1/5

3 0

2 years ago

A race car can travel 2 laps In 10 minutes How long will it take the race car to complete 100 laps at that rate ?

34kurt

Answer:

500 minutes

Step-by-step explanation:

Ok, so the first thing we want to do is figure out how long it takes to complete one lap.

So if it takes 10 minutes to travel 2 laps lets find out how many minutes for one.

It would be 5 minutes for one lap, if you divide 10 by 2 because of the 2 laps.

Next, you just multiply the 5 minutes by 100 laps:

This gives you 500 minutes.

Hope this helps :)

5 0

2 years ago

Read 2 more answers

At Meadowsweet restaurant, Kevin bought 2 burgers, 2 cake slices, and 1 soda. The burgers cost $1.75 each, the cake slices cost

Elenna [48]

Answer:

He should pay 30 quarters

Step-by-step explanation:

To find the number of quarter dollars he should pay, first calculate out the amount of money this would cost. For this, we can multiply the cost of the item by the number of them that we got and then add them all together.

Burgers

2 * 1.75 = 3.50

Cake

2 * 1.50 = 3.00

Soda

1 * 1.00 = 1.00

Total

3.50 + 3.00 + 1.00 = 7.50

Now to find out how many quarters he should pay, we divide the amount by .25.

7.50/.25 = 30

4 0

3 years ago

Simplify cotø(tanø+cotø)

Sladkaya [172]

Answer:

$\large\boxed{\cot\theta(\tan\theta+\cot\theta)=1+\cot^2\theta=\dfrac{1}{\sin^2\theta}=\csc^2\theta}$

Step-by-step explanation:

$\text{Use}\\\\\text{distributive property:}\ a(b+c)=ab+ac\\\cot\alpha\tan\alpha=1.\\\\======================\\\\\cot\theta(\tan\theta+\cot\theta)=(\cot\theta)(\tan\theta)+(\cot\theta)(\cot\theta)\\\\=1+\cot^2\theta\\\\\text{If you want next transformation, then use:}\\\\\cot\alpha=\dfrac{\cos\alpha}{\sin\alpha}\\\\\sin^2\alpha+\cos^2\alpha=1\\\\=======================$

$=1+\left(\dfrac{\cos\theta}{\sin\theta}\right)^2=1+\dfrac{\cos^2\theta}{\sin^2\theta}=\dfrac{\sin^2\theta}{\sin^2\theta}+\dfrac{\cos^2\theta}{\sin^2\theta}=\dfrac{\sin^2\theta+\cos^2\theta}{\sin^2\theta}\\\\=\dfrac{1}{\sin^2\theta}\\\\\text{If you want next transformation, then use:}\\\\\csc\alpha=\dfrac{1}{\sin\alpha}\\\\=\left(\dfrac{1}{\sin\theta}\right)^2=(\csc\theta)^2=\csc^2\theta$

4 0

3 years ago