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Harrizon [31]
3 years ago
12

Is 9.55x10 to the 3rd power greater than less than or equal to 5,900

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

9.55 * 10^3 = 9550.

So it is greater than 5,900.

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Elena-2011 [213]

Answer:

A)2/1

Step-by-step explanation:

the x is one apart ans it whent up 2 to the right 1

5 0
3 years ago
Read 2 more answers
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Find cot theta if 180° < theta < 270° and cos theta = - sqrt 3/2
avanturin [10]

Answer:

cot theta = -√3

Step-by-step explanation:

we are given that  cos theta = - √3/2 within the range 180° < theta < 270° and

since cos theta = adj/hyp

adj = - √3

hyp = 2

Get the opposite using the pythagoras theorem

hyp^2 = opp^2 + adj^2

2² = opp² + (-√3)²

4 = opp² + 3

opp² = 4-3

opp² = 1

opp = 1

tan theta = opp/adj

tan theta = - 1/√3

Recall that cot theta = 1/tan theta

cot theta = 1/(-1/√3)

cot theta = -√3

8 0
3 years ago
If you stand next to a wall on a frictionless skateboard and push the wall with a force of 36 N, how hard does the wall push on
VARVARA [1.3K]

The wall pushes back with an equal and opposite force. So it pushes with a force of 36N in the opposite direction of the push. This allows you to move away from the wall.

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The ratio of the circumferences of two circles 2 : 5. Find the ratio of their areas
ratelena [41]
Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
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4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
5 0
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