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jek_recluse [69]
2 years ago
7

A bag contains 40 coins, all of them are either 2 cent or 5 cent coins. If the value of the money in the bag is $1.55, find the

number of each kind*.
*Use a simultaneous equation to find the number of each.
Mathematics
1 answer:
dlinn [17]2 years ago
5 0

Answer: Explanation:First, let's call the number of 2 cent coins: tNext, let's call the number of 5 cent coins: fWe can then write to equations from the information in the problem.Equation 1: t+f=40Equation 2: 0.02t+0.05f=1.55Step 1) Solve the first equation for t:t+f=40t+f−f=40−ft+0=40−ft=40−fStep 2) Substitute (40−f) for t in the second equation and solve for f:0.02t+0.05f=1.55 becomes:0.02(40−f)+0.05f=1.55(0.02×40)−(0.02×f)+0.05f=1.550.80−0.02f+0.05f=1.550.80+(−0.02+0.05)f=1.550.80+0.03f=1.550.80−0.80+0.03f=1.55−0.800+0.03f=0.750.03f=0.750.03f0.03=0.750.030.03f0.03=25f=25Step 3) Substitute 25 for f in the solution to the first equation at the end of Step 1 and calculate t:t=40−f becomes:t=40−25t=15The Solution Is:There are:15 two cent coins25 five cent coins

Step-by-step explanation:

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IRISSAK [1]

Answer:

x = 10

Step-by-step explanation:

In the last step, you can see that the fraction \frac{1}{5} has been multiplied by its reciprocal \frac{5}{1}, making it cancel out. The reciprocal has been multiplied to both sides, so all you need to do is multiply \frac{6}{3} · \frac{5}{1} :

6 · 5 = 30

3 · 1 = 3

<u><em>So now you should have the fraction:</em></u>

x = \frac{30}{3}

<u><em>But, you can still simplify the fraction by dividing 30 by 3:</em></u>

x = 10

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3 years ago
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Damm [24]

Answer:

it is at -2 degrees

Step-by-step explanation:

sorry for being late but if anyone in the future sees this hears the answer!

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6 0
3 years ago
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PLZ HELP! I will give brainliest! A theater can hold 160 giants or 240 elves. If 100 giants are inside, how many elves can also
slava [35]

Answer:

150

Step-by-step explanation:

100 : 160 :: e : 240     proportion

160e = (100)(240)

160e = 24000

elves = 150

6 0
3 years ago
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How do you make 'a' the subject of the formula: ab - cd = ac
xxTIMURxx [149]
First bring all terms in 'a' to the left side of the formula by subtracting ac from both sides

ab - ac - cd = ac - ac 
ab - ac - cd = 0
now add cd to both sides
ab - ac -cd + cd = cd
ab - ac = cd
now factor the left side by taking out the 'a' 
a(b-c) = cd
now divide both sides by (b-c)
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3 0
3 years ago
Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)
Elan Coil [88]

Answer:

10u^{3}+4u^{2}-2u+10 or 2(5u^{3}+2u^{2}-u+5)

Step-by-step explanation:

we have

(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)

step 1

Group terms that contain the same variable

(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)

step 2

Combine like terms

(10u^{3})+(4u^{2})+(-2u)+(10)

step 3

Eliminate parenthesis

10u^{3}+4u^{2}-2u+10

step 4

Factor the number 2

2(5u^{3}+2u^{2}-u+5)

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