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Travka [436]
3 years ago
15

What is the domain of the function in this table

Mathematics
1 answer:
lina2011 [118]3 years ago
5 0

For this case we have that by definition, the domain of a function is given by the set of all the possible input values of the function. That is, the values that the variable "x" takes.

Also, it can be said that it is the set of all the values for which the function is defined.

The table shows that "x" takes the following values:

{3,4,5,6}

Answer:

Domain: {3,4,5,6}

Option C

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Which expression is equivalent to 8 (a minus 6)?<br> 8 a minus 48<br> 2a<br> 8 a minus 6<br> 48a
frozen [14]

Answer:

8 a minus 48

Step-by-step explanation:

you need to distribute!!

so you distribute the 8 to both the a and 6

8 times a equals 8 a

8 times 6 equals 48

and so that’s how you get 8 a minus 48 c:

4 0
2 years ago
I need help quick so I can play outside
kvasek [131]

Answer:

its a but you get recess in virtual school???????

8 0
3 years ago
Consider the set n of positive integers to be the universal set. sets​ h, t,​ e, and p are defined to the right. determine wheth
noname [10]

Answer:

The sets E' and P' are not disjoint.

Step-by-step explanation:

Definition: Two sets are disjoint if their intersection is an empty set.

The sets are defined as follows.

\text{Universal Set}, U=\{n|n \in \mathbb{Z}^+\},$ where  \mathbb{Z}^+$ is the set of positive integers.

H=\{n|n \in \mathbb{N}| n>100\}\\T=\{n|n \in \mathbb{N}| n

We are to determine if the sets E' and P' are disjoint.

E' and P' are the complements of E and P respectively.

Therefore:

E'=\{n|n \in \mathbb{N}| n$ is odd$\}\\P'=\{n|n \in \mathbb{N}| n$ is not prime\}

The intersection

E' \cap P' =\{n|n \in \mathbb{N}| n$ is odd but not prime$\}

Therefore, the sets E' and P' are not disjoint.

7 0
3 years ago
Someone please help me with this
Nataly_w [17]

Answer:

a.\ D=\dfrac{1}{5}t

b. 20 seconds

Step-by-step explanation:

Let D be the distance in miles and

t be the time in seconds and

s be the speed in miles/sec

Formula for Distance is given as:

Distance = Speed \times Time\\OR\\D=st

Given that:

Distance = 2 miles and

Time = 10 seconds

Putting the values in formula:

2=s\times 10\\\Rightarrow s =\dfrac{1}{5} \ miles/sec

<em>Answer a:</em>

Putting the value of s back in the formula to find the <em>direct variation equation </em>for the relationship between time and distance:

D=\dfrac{1}{5}t

<em>Answer b:</em>

Using the above formula and putting D=4\ miles:

4=\dfrac{1}{5}t\\\Rightarrow t =\bold{20\ seconds}

7 0
3 years ago
HELP!! WORTH 20 POINTS
Rom4ik [11]

( anything )² = anything × anything

5² = 5 × 5 = 25


8 0
4 years ago
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