You start off by multiplying the second bracket by -1 to get rid of the bracket.
So,
(2x3 + x2 - 4x) - 9x3 + 3x2 =
2x3 +x2 - 4x - 9x3 + 3x2 =
(2x3 - 9x3) + (x2 + 3x2) - 4x =
-7x3 + 4x2 - 4x

7 0

3 years ago

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I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha

Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = $\frac{\theta}{360}(\pi r^{2})$

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = $\frac{60}{360}(\pi) (10^{2})$

= 52.36 in²

Area of equilateral triangle BCD = $\frac{\sqrt{3} }{4}(\text{Side})^2$

= $\frac{\sqrt{3} }{4}(10)^2$

= $25\sqrt{3}$ in²

= 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

= 9.06 in²

Area of sector CAD = $\frac{90}{360}(\pi)(\sqrt{50})^2$

= 39.27 in²

Area of right triangle CAD = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(\text{AC})(\text{AD})$

= $\frac{1}{2}(\sqrt{50})(\sqrt{50})$

= 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

= 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

= 23.33 in²

8 0

2 years ago

Mattis saving to buy a new motorcycle. If he deposits $50 at the end of each month in an account that pays an annual interest ra

liq [111]

In thirty months you should have 5,250.00

4 0

3 years ago