Help this is geometry! Help me please!

Mathematics

1 answer:

gulaghasi [49]3 years ago

7 0

You can use the triangle congruence theorem here because the hypotenuse and the leg of the two right triangles align.

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You just discovered that you have 100 feet of fencing and you have decided to make a rectangular garden. What is the largest are

Rudik [331]

The area is:
A = x * y
The perimeter is:
P = 2x + 2y = 100
We clear y:
2y = 100-2x
y = 50-x
We write the area in terms of x:
A (x) = x * (50-x)
Rewriting:
A (x) = 50x-x ^ 2
Deriving:
A '(x) = 50-2x
We equal zero and clear x:
50-2x = 0
x = 50/2
x = 25
Then, the other dimension is given by:
y = 50-x
y = 50-25
y = 25
Therefore, the largest area is:
A = (25) * (25)
A = 625 feet ^ 2
Answer:
the largest area you can enclose using the materials you have is:
A = 625 feet ^ 2

8 0

4 years ago

15. If y varies directly as x and y = 540 when x = 10, find x when y = 1080

Sholpan [36]

$\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{\textit{"y" varies directly as "x"}}{y = kx}\qquad \textit{we also know that} \begin{cases} y = 540\\ x = 10 \end{cases}\implies 540=k(10) \\\\\\ \cfrac{540}{10}=k\implies 54=k~\hfill \boxed{y=54x} \\\\\\ \textit{when y = 1080, what is "x"?}\qquad 1080=540x\implies \cfrac{1080}{540}=x\implies 2=x$