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allsm [11]
3 years ago
13

What is the domain of f(x) 5^x-7?

Mathematics
1 answer:
kherson [118]3 years ago
3 0
Domain is the set of number you can use for x we can use any number for x the domain is all real numbers answer is last one
You might be interested in
The width of a rectangular poster is 16 in its length is twice its width find the perimeter
Evgesh-ka [11]
Length = x
width = y

y = 16
x = 2y
x = 2(16)
x = 32

perimeter = 2x + 2y
= 2(32) + 2(16)
= 64 + 32
= 96
6 0
3 years ago
jackson wants to divide 3\4 pound box of trail mix into small bags each of the bags will hold 1/12 pound of trail mix how many b
guapka [62]
(3/4) / (1/12)...when dividing with fractions, flip what u r dividing by, then multiply

3/4 * 12/1 = 
36/4 =
9 bags <===
5 0
3 years ago
For the function y = 4x - 11, what is the ordered pair for x = 2?
Nonamiya [84]

Answer:

(2, -3)

Step-by-step explanation:

Plug x = 2 into the equation y = 4x - 11

y = 4(2) - 11

y = 8 - 11

y = -3

Then, put x = 2 and y= -3 into an ordered pair.

(2, -3)

7 0
2 years ago
Read 2 more answers
A number cube with sides labeled 1 through 6 is rolled two times, and the sum of the numbers that end face up is calculated. Wha
Orlov [11]
Desirable outcomes are 1,2 or 2,1

total outcomes are 6*6=36

so, P=2/36=1/18
5 0
3 years ago
1+2+3+4+5+.........+100= ?<br> The sum of 100 consecutive interger from 1 to 100
Mama L [17]

Answer:

5050

Step-by-step explanation:

Ace here!

So, you could go through and add up everything but that takes a while, and there's a much easier way to do this. Let's write a rough sample of the numbers.

1, 2, 3, 4, 5....96, 97, 98, 99, 100.

Now, let's look at these numbers. Notice how if we add the two numbers on the leftmost and the rightmost, we get 101 (1+100). Now, we do 1 from the left added on to one from the right, and get 101(2+99). Then, we can follow that pattern and do 3+98=101, 4+97=101, and as long as we follow that pattern, we keep getting 101 as our answer.

Now, if we keep going with this, eventually we will get to 48+53, 49+52, 50+51.

If we supposedly counted all these pairs, we would find we have 50 pairs. But a quick way to check is to just divide 100 by 2 (100/2) and we get 50.

Now, we have 50 pairs that add up to 101. So, that would be 101 added to itself 50 times, which is just multiplication. 101 × 50 which is 5050.

I hope this helped. Let me know if you have any questions.

6 0
3 years ago
Read 2 more answers
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