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k0ka [10]
3 years ago
14

Round 3..............almost out of points .-.

Mathematics
2 answers:
Sidana [21]3 years ago
8 0
You can use a proportion.

2/3 inch is to 1 hour as 6 2/3 inch is to x hours.

\dfrac{\frac{2}{3}~inch}{1~hour} = \dfrac{6 \frac{2}{3}~inch}{x}

Cross multiply to get

\dfrac{2}{3} x = 6 \dfrac{2}{3}

\dfrac{2}{3} x = \dfrac{20}{3}

2x = 20

x = 10

Answer: It rained for 10 hours.
Dovator [93]3 years ago
4 0
6 2/3 ÷ 2/3
= 20/3 ÷ 2/3
= 20/3 × 3/2
= 20/2
= 10

Answer
10 hours
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The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is th
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Answer:

a + b \geq 30

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Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

a + b \geq 30

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

b - a \geq 10

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

a + b \geq 30

b - a \geq 10

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Mademuasel [1]

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Step-by-step explanation:

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