Question

A spherical object has a diameter of 18 cm. It has a spherical inner core with a diameter of 9 cm. What is the volume of the outer layer? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box. Cm³.

Answer 1

The volume of the outer layer is 2670.57 cubic centimeters.

Given

The aspherical object has a diameter of 18 cm.

It has a spherical inner core with a diameter of 9 cm.

The volume of outer layer;

The volume of the outer layer is given by the following formula;

$\rm Volume=\dfrac{4}{3}\pi r^3$

The volume of the outer layer is given by;

Entire sphere - Inner sphere= Outer layer

Radius of Entire sphere = 9 cm

Radius of Inner sphere = 4.5 cm

Therefore,

The volume of the outer layer is;

$\rm Volume=\dfrac{4}{3}\pi [(Entire \ sphere)^3 - (Inner \ sphere)^3]\\\\Volume=\dfrac{4}{3}\pi (9^3-4.5^3)\\\\Volume=\dfrac{4}{3}\pi(729-91.12)\\\\Volume=\dfrac{4}{3}\times 3.14 \times 637.88\\\\ Volume = 2670.57$

Hence, the volume of the outer layer is 2670.57 cubic centimeters.

To know more about volume click the link given below.

brainly.com/question/26572966

Answer 2

Answer:

2,670.57 cm cubed

Step-by-step explanation:

The whole sphere (outer and inner combined) = 3,052.08  inner sphere = 381.51

3,052.08 - 381.51 is 2,670.57

please tell me if this is wrong, this is my first time doing this type of thing but i am 99% sure its correct