ANSWER THIS FOR ALL MY POINTS, ALSO BRAINLIEST
1 answer:
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Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer
Answer:
and
Step-by-step explanation:
GIVEN: an array of ten integers .
TO FIND: If we partition this array using Quick sort's partition function and using for the pivot. List the elements of the resulting array after the partition finishes.
SOLUTION:
quick sort is a divide and conquer algorithm in which an array is partitioned into sub-arrays about an pivot element by checking whether elements are greater than pivot or and then sub arrays are sorted recursively.
Here is the pivot element.
two arrays will be created, in first array element less than or equal to pivot element are stored in other elements greater than pivot element are stored.
Starting from first element of array
elements in first array will be
elements in second array will be
Hence the resulting array after the partition finishes are and