B- 1/2 the books are science books. You have to add the two fractions and subtract that from one.
Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
Answer:
<h2>x = 3 and y = 4</h2>
Step-by-step explanation:
We know:
The diagonals in a parallelogram divide by halves.
Therefore KG = UG and DG = CG.
We have
KG = 5y - 8, UG = 3y, DG = 4x - 7, CG = x + 2
Substitute:
5y - 8 = 3y <em>add 8 to both sides</em>
5y = 3y + 8 <em>subtract 3y from both sides</em>
2y = 8 <em>divide both sides by 2</em>
y = 4
---------------
4x - 7 = x + 2 <em>add 7 to both sides</em>
4x = x + 9 <em>subtract x from both sides</em>
3x = 9 <em>divide both sides by 3</em>
x = 3
Answer: 5.64 *10^2
Step-by-step explanation:
