Question

Help me i'll give brainlist

Answer 1

Answer:

$x=\frac{1}{2}$

Step-by-step explanation:

equation of a circle:  $(x - h)^2+(y-k)^2=r^2$

where (h, k) = center and r = radius

From inspection, we can see that the center of the circle = (0, 0)

and the radius = 1

$\implies (x - 0)^2+(y-0)^2=1^2$

$\implies x^2+y^2=1$

Substitute $y=\frac{\sqrt{3}}{2}$  into  $x^2+y^2=1$  and solve for $x$:

$\implies x^2+(\frac{\sqrt{3}}{2})^2=1$

$\implies x^2+\frac{3}{4}=1$

$\implies x^2=\frac{1}{4}$

$\implies x=\pm \sqrt{\frac{1}{4}}$

$\implies x=\pm\frac{1}{2}$

As point P is in quadrant 1, $x$ is positive, so $x=\frac{1}{2}$