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3 years ago

Statement that explains how the values of 36 and 360 are different.

Mathematics

1 answer:

wolverine [178]3 years ago

3 0

360 is 10 times as much as 36

They end in different place values as well

Thank me later :)

(or just mark as brainliest)

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Calculate the number of litres of water in the tank

notsponge [240]

Answer:

SEE IMAGE FOR SOLUTION

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Step-by-step explanation:

900 litres

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3 years ago

Lindy works at a pizza restaurant and gets a 10% employee discount. She knows that if she orders d drinks and a medium pizza wit

timofeeve [1]

Answer:

$17.28.

Step-by-step explanation:

In the expression, d represents the number of drinks she orders and t represents the number of toppings.

In this case, she orders 4 drinks and 3 toppings, so d = 4 and t = 3.

0.90(2.25d + 1.40t + 6)

= 0.9(2.25 * 4 + 1.4 * 3 + 6)

= 0.9(9 + 4.2 + 6)

= 0.9 * 19.2

= 17.28

So, the total cost for Lindy and her friends will be $17.28.

Hope this helps!

8 0

4 years ago

I will gave brainestly

hammer [34]

Answer:

Hello !

The solutions are: -8 , -4 , 6

Hope this helps !

3 0

3 years ago

If c(x)=5/x-2 and d(x)=x+3 what is the domain of (cd)(x)?. . And, if f(x)=7+4x and g(x)=1/2x, what is the value of (f/g)(5)?

Vesna [10]

1. The value of (cd)(x) is equal to the product of c(x) and d(x) which is equal to,
5(x + 3) / (x - 2)
The function can take all real numbers except 2 because that would make the denominator 0.

2. To answer, substitute first 5 to the given functions,
f(x) = 7 + 4x = 7 + 4(5) = 27
g(x) = 1/2x = 1 / (2)(5) = 1/10
Dividing 27 by 1/10 is 270.

3 0

4 years ago

Read 2 more answers

A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. Supp

Trava [24]

Answer:

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

Step-by-step explanation:

As the test is targeted to 18-to-29-year-old adults using social media, we want to know the probability that a randomly selected adult uses social media and belong to the study group.

To achieve this, we have this data:

- 36% of all adults do not use social media

- 75% of all adults are >30 years old.

- The percentage of population that is either 18-29 years old or uses social media is 66.7%

Using the last data we have that

$P(social\,media=yes\, or\,18-29=yes)=P(social\,media=yes)+P(18-29=yes)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=(1-0.36)+(1-0.75)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=0.64+0.25-P(social\,media=yes\, \&\,18-29=yes)\\\\P(social\,media=yes\, \&\,18-29=yes)=0.64+0.25-0.667=0.223$

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

8 0

3 years ago