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3 years ago

Statement that explains how the values of 36 and 360 are different.

Mathematics

1 answer:

wolverine [178]3 years ago

3 0

360 is 10 times as much as 36

They end in different place values as well

Thank me later :)

(or just mark as brainliest)

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How to write out $103,716.68

Degger [83]

One hundred three thousand seven hundred sixteen dollars and sixty eight cents

8 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago

Write an equation of the line that passes through a pair of points:

Shalnov [3]

Answer:

Step-by-step explanation:

(-2,-2) , (5,-5)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-5-(-2)}{5-(-2)}\\\\=\frac{-5+2}{5+2}\\\\=\frac{-3}{7}\\$

(-2,-2), m= -3/7

Line equation: y -y1 =m*(x -x1)

y-(-2) = -(-3/7)(x - [-2])

$y+2=\frac{-3}{7}*(x+2)\\\\y+2=\frac{-3}{7}*x+(\frac{-3}{7})*2\\\\y+2=\frac{-3}{7}x-\frac{6}{7}\\\\y=\frac{-3}{7}x-\frac{6}{7}-2\\\\y=\frac{-3}{7}x-\frac{6}{7}-\frac{2*7}{1*7}\\\\y=\frac{-3}{7}x-\frac{6}{7}-\frac{14}{7}\\\\y=\frac{-3}{7}x-\frac{20}{7}$

4 0

3 years ago

Read 2 more answers

Please help me ASAP !!!! Will give brainliest!!!!!! Please Answer the image below.

JulijaS [17]

Answer:

I think it’s the first and fourth

Step-by-step explanation:

Hope this helps!!!!

3 0

3 years ago

The sum of the digits of a two-digit number is 11. When the digits are reversed, the new number is 45 more than the original num

Crank

Answer:

Step-by-step explanation:

Let the 10s digit = x

Let the units digit = y

x +y = 11 Sum of the digits = 11

10x + y + 45 = 10y + x Reversed number is 45 more than original #

10x - x + y + 45 = 10y We subtracted x from both sides.

9x + y + 45 = 10y Subtract y from both sides.

9x + 45 = 10y - y Combine the right

9x + 45 = 9y

Put x + y = 11 into the equation just found.

9x + 45 = 9(11 - x) divide through by 9

x + 45/9 = 11 - x add x to both sides

2x + 5 = 11 Subtract 5 from both sides

2x = 11 - 5

2x = 6 Divide by 2

x = 6/2

x = 3

x + y = 11

3 + y = 11

y = 11 - 3

y = 8

Now check it out.

the original number is 38

the new number is 83 which the digits are reversed.

83 - 38 = 45 just as it should.

6 0

2 years ago