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lianna [129]
3 years ago
8

...................

Mathematics
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

easey, sub them

(x,y)

see if true

(0,1), 2(0)+1>-4, 1>-4, true

(4,-12), 2(4)+-12>-4, 8-12>-4, -4>-4, false

(5,-12), 2(5)+-12>-4, 10-12<-4, -2>-4, true

(-1,-1), 2(-1)+-1>-4, -2-1>-4, -3>-4, true

(-3,0), 2(-3)+0>-4, -6>-4, false

answers are

(0,1)

(5,-12)

(-1,-1)

Hopefully that helped you a little bit :)

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The mid-point between the endpoints (10,5) and (6,9) is:

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Step-by-step explanation:

Let (x, y) be the mid-point

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Here:

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\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

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Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
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