Answer:
r=12 as answer but as you will have reflective numbers (r12+2)(10x10)=3 in this sort of equation you will see that as they grew at a 88.3% rate 5/6 and 0.16 is a per month rate the coefficient value we can round down and call r12 = 6 for step 2 in the equation. As we can also find +0.88 which rounds to 1 and 0.33 the rate of change per month rounds to -1 and -100/12=8.3 if you are looking for the percentage. To find 6 we only need to 10/10 = 1. It is important you keep an equation simple for the growth as the change in measurement will always need a new percentage and we have a base number that can show such percentage as if it changed to 100% again at 12 inches we could reuse the equation =3-2=1 etc. or r12/100 =0.88 r=rise percentage and also be divided into 2 if we call r12 and r2 in same first equation to make r6.
Step-by-step explanation:
Answer:
-308
Step-by-step explanation:
Hope that helped!
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
You have to plot 10 on number line
Just Move 10 units Forward From O(zero or origin) to locate it
There is no greatest perimeter of a rectangle with an area of 39 square feet.
To see why, consider the length of 3 and width of 13. Area would be 39 and perimeter would be 3 + 3 + 13 + 13 = 32
Now consider length of 3/2 = 1.5 and 13·2 = 26. Then area is same but perimeter is 1.5 + 1.5 + 26 + 26 = 55.
Now we can just repeatedly half the length and double the width.
L = 3.0, W = 13
⇒ A = 39, P = 32.0
L = 1.5, W = 26
⇒ A = 39, P = 55.0
L = 0.75, W = 52
⇒ A = 39, P = 105.5
L = 0.375, W = 104
⇒ A = 39, P = 208.75
L = 0.1875, W = 208
⇒ A = 39, P = 416.375
L = 0.09375, W = 416
⇒ A = 39, P = 832.1875
L = 0.046875, W = 832
⇒ A = 39, P = 1664.09375
L = 0.0234375, W = 1664
⇒ A = 39, P = 3328.046875
L = 0.01171875, W = 3328
⇒ A = 39, P = 6656.0234375
L = 0.005859375, W = 6656
⇒ A = 39, P = 13312.01171875
Notice how P just kept growing. That's because width grow much faster than length <span>shrinking, </span>so P would grow endlessly.
Hope this helps.
