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3 years ago

How many terms does the polynomial have? a 2 + b - cd 3 2 3 4

Mathematics

1 answer:

vaieri [72.5K]3 years ago

7 0

ANSWER

EXPLANATION

The given polynomial is

${a}^{2} + b - cd$

The terms of the polynomial are:

First term:

${a}^{2}$

Second term:

$b$

Third term:

$- cd$

Therefore the given polynomial has 3 terms.

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If cos 0=2/3, what are the values of sin 0 and tan 0?

morpeh [17]

Answer:

Below

Step-by-step explanation:

● cos O = 2/3

We khow that:

● cos^2(O) + sin^2(O) =1

So : sin^2 (O)= 1-cos^2(O)

● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9

● sin O = √(5)/3 or sin O = -√(5)/3

So we deduce that tan O will have two values since we don't khow the size of O.

■■■■■■■■■■■■■■■■■■■■■■■■■

●Tan (O) = sin(O)/cos(O)

● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)

● tan (O) = √(5)/2 or tan(O) = -√(5)/2

4 0

3 years ago

Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (

Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138 (1)

The second equation in the unknowns is

3B + 5N = 71 (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===> 40B + 30N = 690 (3)

Multiplying (2) by 6 ===> 18B + 30N = 426 (4)

(3) - (4) eliminates the N variables and yields

22B = 264 ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==> 36 + 5N = 71 ==> 5N = 71-36 = 35 ==> N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0

1 year ago

Need help with two word problems

dangina [55]

Answer:

E. 18 children are buying their lunches

F. Rock must pay $50 each month

Step-by-step explanation:

To find a percentage you multiply the number by the percentage;

60 x 70%(0.70) = 42 children brought their lunches

But we need the amount <u>buying</u> their lunches so we would subtract 60 by 42;

60 - 42 = 18 buying their lunches

Again, to find the percentage we multiply it by the original;

$800 x $25(0.25) = $200 Rock paid for the down payment on the sofa

Now we need to find how much Rock still needs to pay for the sofa;

$800 - $200 = $600 more needed to pay for the sofa

Lastly, we must find how much Rock will need to pay <u>each month</u> to pay the rest of the $600. There are 12 months in a year, so we divide that by the amount left;

$600 / 12 = $50 needs to be paid each month for a year

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3 years ago

Sorry for my laziness I kinda didn’t pay attention well I did but I was confused the whole time just please someone ANSWER OR JU

Svetradugi [14.3K]

What do you need help with?!

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3 years ago

Erika had three pieces of ribbon . Each piece is 25 yards long. She needs to cut pieces that are 22 inches long . What is the gr

Kisachek [45]

B. 120 because you cant glue the ribbon together, simply multiply 25 by 3 multiply that by 12 divide that by 22 then multiply that by 3

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3 years ago