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Leviafan [203]
2 years ago
14

What is a business opportunity?

Business
1 answer:
Hunter-Best [27]2 years ago
3 0

Answer:

A business opportunity, in the simplest terms, is a packaged business investment that allows the buyer to begin a business. (Technically, all franchises are business opportunities, but not all business opportunities are franchises.) Unlike a franchise, however, the business opportunity seller typically exercises no control over the buyer's business operations. In fact, in most business opportunity programs, there's no continuing relationship between the seller and the buyer after the sale is made.
Although business opportunities offer less support than franchises, this could be an advantage for you if you thrive on freedom. Typically, you won't be obligated to follow the strict specifications and detailed program that franchisees must follow. With most business opportunities, you would simply buy a set of equipment or materials, and then you can operate the business any way and under any name you want. There are no ongoing royalties in most cases, and no trademark rights are sold.

Business opportunities are difficult to define because the term means different things to different people.

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________ policies refer to government programs designed to exploit natural comparative advantage by increasing production of a f
Setler [38]

Answer:

Primary-export-led development

Explanation:

Primary-export-led development policies refer to government programs designed to exploit natural comparative advantage by increasing production of a few export goods most closely related to a country's resource base.

5 0
3 years ago
An association had a fund balance of 75 on January 1 and 60 on December 31. At the end of every month during the year, the assoc
ValentinkaMS [17]

Answer: 0.11 or 11%

Explanation: The dollar-weighted return (DWR) measures the rate of return of an investment or a portfolio, taking under consideration the timing of flows. for every deposit, add the resulting amount to the start balance, and for every withdrawal, subtract that quantity. Check the attachment for the solution.

Once you've got both numbers, divide the first by the second. which will offer you the dollar-weighted investment return, which you'll then multiply by 100 to give you a return in percentage terms.

3 0
3 years ago
Deadweight loss occurs when
dusya [7]

Answer:

d) the maximum level of total welfare is not achieved.

Explanation:

When the economic efficiency bears a loss, it is termed to be a deadweight loss. This condition occurs in the situation when the free market equilibrium is not able to be achieved. It occurs in the economy when the supply and the demand for the goods and services start to fall from being in the state of equilibrium. The resources allocated experiences a deficiency, thereby causing a deadweight loss.

3 0
3 years ago
Solution Enterprises incurred $828,000 of fixed overhead during the period. During that same period, the company applied $845,00
Wewaii [24]

Answer:

Budgeted fixed overhead= $787,000

Explanation:

Budget variance = Actual overhead-budgeted overhead

-41000 = 828000-X

X = 787000

So answer is $787000

5 0
3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
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