Answer:
a. $29.23
b. $146,150
Explanation:
a. The computation of overhead application rate is shown below:-
Overhead application rate = Total standard overhead ÷ Total standard hours
= $163,710 ÷ (1,120 × 5)
= $163,710 ÷ 5,600
= $29.23
So, for determining the overhead application rate we simply divide the total standard overhead by total standard hours.
b. The computation of overhead was applied to production is shown below:-
Applied overhead = Standard hours for actual production × Overhead application rate
= 5,000 × $29.23
= $146,150
So, for determining the applied overhead we simply divide the standard hours for actual production by overhead application rate
Answer:
the net book value of the asset halfway through its useful life will be less than if straight-line depreciation is used.
Explanation:
Let me use an example to illustrate this.
An asset has a useful life of 4 years. It costs $1000. It has a salvage value of 0
If the straight line depreciation method is used , the depreciation expense every year = $1000/ 4 = $250
The net book value halfway through its useful life = $1000 - ($250 x 2) = $500
If double declining method is used, the depreciation expense in the first year would be = 2/4 x $1000 = $500
The net book value at the beginning of year 2 = $1000 - $500 = $500
Depreciation expense in year 2 = 2/4 x $500 = $250
The net book value at the beginning of year 3 = $500 - $250 = $250
We can see that the net book value halfway through the useful is lower when double declining depreciation method is used
Answer:
The lease payment will be for $ 113,751.173 during 5 years beginning at the moment the lease is signed
Explanation:
First, we discount the payment at the end of the lease
Maturity $150,000
time 5 years
rate 0.06
PV 112,088.7259
Now we subtract form the 620,000 to know the amount to be perceived form the lease payment:
620,000 - 112,089 = 507.911
Now we solve the PMT which makes the annuity-due of 5 payment at the beginning of the period:
PV $507,911.0000
time 5
rate 0.06
[tex ]507,911 \div \frac{1-(1+0.06)^{-5} }{0.06}(+0.06) = C\\[/tex]
C $ 113,751.173
