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nasty-shy [4]
3 years ago
10

Exercises 1. Polygon ABCD has vertices A(2,4), B(-1,5), C(-3,-5), and D(3,-4). Find the coordinates of its image after a dilatio

n with a scale factor of. Then graph polygon ABCD and its dilation. 2​
Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0

Answer:

Ok Sorry but please tell me how r u seeing my comments so fast?

Step-by-step explanation:

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Y
Genrish500 [490]

We need to find two relations, and use them to find the value of y when z = 15.

We will see that the value of y in that case is 4,860.

We know that <u>y  varies inversely with the square of  x</u>, also <u>y  is also proportional to the cube of  z</u>

Then we can write:

y = k/x^2

y = c*z^3

We also know that:

When x = 3, y = 80.

Replacing that in the first equation to find the value of k:

80 = k/3^2

80 = k/9

80*9 = k = 720

We also know that when x = 2, z = 5

From the first relation we have:

y = 720/2^2 = 720/4 = 180

Now we replace this in the equation of y and z:

y = c*z^3

180 = c*5^3

180 = c*125

180/125 = c = 1.44

Now we need to calculate y when z = 15, then we just need to replace z by 15 in the equation for y and z:

y = 1.44*(15)^3 = 4,860.

If you want to learn more, you can read:

brainly.com/question/2548537

8 0
3 years ago
What are the solutions to the equation x2 + 6 = 87? A. –10 and 10 B. The equation has no solutions. C. –6 and 6 D. –9 and 9
kakasveta [241]
X² + 6 = 87
<u>     - 6   - 6</u>
       x² = 81
       x = <u>+</u>9
x = 9    U    x = -9
The solution set is equal to D. {<u>+</u>9}.
8 0
4 years ago
Im unclear on which side of my graphed linear inequality to shade in. How do I know which side to shade in??
Tems11 [23]
If the inequality is greater than, you shade above. If it is less than, you shade below
6 0
4 years ago
Read 2 more answers
Can someone help me with this problem://
fiasKO [112]

You can simply collect terms, subtract the constant and divide by the x-coefficient. It is generally considered easier to do those steps if you eliminate fractions first (multiply by 12).

Multiply by 12

... 4(x -1) +3(x +5) = 6

... 4x -4 +3x +15 = 6 . . . . . eliminate parentheses

... 7x +11 = 6 . . . . . . . . . . . .collect terms

... 7x = -5 . . . . . . . . . . . . . . subtract the constant 11

... x = -5/7 . . . . . . . . . . . . . divide by the x-coefficient

_ _ _ _ _ _ _

Here it is the other way.

... x(1/3 +1/4) +(-1/3 +5/4) = 1/2

... (7/12)x + 11/12 = 1/2 . . add the fractions to finish collecting terms

... x + 11/7 = 6/7 . . . . . . . multiply by 12/7

... x = -5/7 . . . . . . . . . . . subtract 11/7

At the third step here, you could subtract 11/12 before doing the multiply. You get the same answer, but you have to do the extra conversion of 1/2=6/12.

8 0
3 years ago
There are 576 heartbeats on 32 seconds the unite rate is...... heartbeats per second
ohaa [14]

Answer:

18

Step-by-step explanation:

I know this bc, if you divide the heart beats by the seconds you get the answer.

576/32=18

Hope this helps:)

5 0
3 years ago
Read 2 more answers
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