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2 years ago

Can some please help me with this

Mathematics

2 answers:

vlada-n [284]2 years ago

7 0

Answer:

figure a

figure b

figure c

Angelina_Jolie [31]2 years ago

3 0

Answer:

figure a is a parallelogram

figure b is a square

figure c is a rectangle

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3 years ago

Hello, can someone help me with this problem?

exis [7]

Answer:

Area of Rectangle A

$Area = 4x^2$

Area of Rectangle B

$Area = 2x^2$

Fraction

$Fraction =\frac{2}{3}$

Step-by-step explanation:

From the attached, we understand that:

The dimension of rectangle A is 2x by 2x

The dimension of rectangle B is x by 2x

Area of rectangle is calculated as thus;

$Area = Length * Breadth$

Area of Rectangle A

$Area = 2x * 2x$

$Area = 4x^2$

Area of Rectangle B

$Area = x * 2x$

$Area = 2x^2$

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The largest rectangle is formed by merging the two rectangles together;

The dimension are 3x by 2x

The Area is as follows

$Area = 2x * 3x$

$Area = 6x^2$

The fraction of rectangle A in relation to the largest rectangle is calculated by dividing area of rectangle A by area of the largest rectangle;

$Fraction = \frac{Rectangle\ A}{Biggest}$

$Fraction =\frac{4x^2}{6x^2}$

Simplify

$Fraction =\frac{2x^2 * 2}{2x^2 * 3}$

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3 years ago

Rewrite the equation to isolate the variable.. df= g- 10 for d

ehidna [41]

Df = g - 10

To solve for d, divide both sides by f.

df / f = (g - 10) / f

d = (g - 10) / f

I hope this explains it.

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