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grigory [225]
2 years ago
7

Can some please help me with this

Mathematics
2 answers:
vlada-n [284]2 years ago
7 0

Answer:

figure a

figure b

figure c

Angelina_Jolie [31]2 years ago
3 0

Answer:

figure a is a parallelogram

figure b is a square

figure c is a rectangle

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What is the slope of the line perpendicular to the line with equation 4x-5y+13=0
motikmotik

Answer:

m = - 5/4

Step-by-step explanation:

If two lines are perpendicular, their slopes are negative reciprocals, which means that their product is -1

We can write the equation

4*x - 5*y + 13  = 0

as:      5*y  =  4*x  + 13      or    

y  = (4/5)*x  + 13        (1)

Equation (1) is the equation of a straight line in its slope point form, 4/5 is the slope, according to this  the slope of a perpendicular line is

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Answer:

x = 4 ±√26

Step-by-step explanation:

Please write this as x^2 - 8x = 10, or x^2 - 8x - 10 = 0.  " ^ " indicates exponentiation.

Let's complete the square:

x^2 - 8 x can be rewritten as

x^2 - 8x + 16 - 16, and so

x^2 - 8x = 10 becomes x^2 - 8x + 16 - 16 - 10 = 0, or

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Taking the square root of both sides, we get:

x - 4 = ±√26, or

x = 4 ±√26

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Sunny_sXe [5.5K]

Answer:

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I am pretty sure . . . . . .

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