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2 years ago

7

Can some please help me with this

2 answers:

vlada-n [284]2 years ago

7 0

Answer:

figure a

figure b

figure c

Angelina_Jolie [31]2 years ago

3 0

Answer:

figure a is a parallelogram

figure b is a square

figure c is a rectangle

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What is an equivalent expression for 24+49

Alexus [3.1K]

Answer:

20 + 4 + 40 + 9

Step-by-step explanation:

20 + 4 is 24 and 40 + 9 is 49, so it's pretty much the same thing.

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3 years ago

Katniss can see a hovercraft 127 feet in the air. She is 95 feet from the spot on the ground directly underneath the hovercraft.

yaroslaw [1]

I DON'T KNOW I'M JUST TRYING TO GET SOME POINTS

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3 years ago

Solution set is(answer)................

kirill [66]

<h3>The solution is x = 27</h3>

To undo a log, you raise both sides as exponents. This will cancel out the log on the left side. On the right side you'll have 6^2 turn into 36.

So you should end up with x+9 = 36 after you perform this step. Afterwards, subtract 9 from both sides to end up with x = 27.

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3 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers

What is 1 2/3 as an improper fraction

nataly862011 [7]

Hi there! To turn a mixed number into a improper fraction we multiply 1 by 3 and add 2. 1 2/3=1×3+2/3=5/3. Therefore, 1 2/3 as an improper fraction is 5/3.

6 0

3 years ago