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3 years ago

1 What is the simplified value of the exponential expression 27'? © malo 03

Mathematics

2 answers:

LenaWriter [7]3 years ago

8 0

Answer: 3

Step-by-step explanation:

Anon25 [30]3 years ago

4 0

Answer:

${27}^{ \frac{1}{3} } = \sqrt[3]{27} = \sqrt[3]{3 \times 3 \times 3} = \boxed{ 3}✓$

<h3>3. 3 is the right answer.</h3>

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4 years ago

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Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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3 years ago

How do i find x? 3(x+2)-3+x+17=40 x should be 5 but i need the steps

alexandr1967 [171]

3(x+2)-3+x+17=40
3x+6-3+x+17=40
4x+20=40
-20 -20
4x=20
/4 /4
x=5

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3 years ago

1 What is the simplified value of the exponential expression 27'? © malo 03​

1 What is the simplified value of the exponential expression 27'? © malo 03