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valina [46]
3 years ago
15

1 What is the simplified value of the exponential expression 27'? © malo 03​

Mathematics
2 answers:
LenaWriter [7]3 years ago
8 0

Answer: 3

Step-by-step explanation:

Anon25 [30]3 years ago
4 0

Answer:

{27}^{ \frac{1}{3} }  =  \sqrt[3]{27}  =  \sqrt[3]{3 \times 3 \times 3}  = \boxed{ 3}✓

<h3>3. <em><u>3</u></em> is the right answer.</h3>
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Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
A sound wave travels through iron at a rate of 5120\,\dfrac{\text{m}}{\text{s}}5120 s m ​ 5120, start fraction, start text, m, e
klio [65]

Answer:

18432 km/h

Step-by-step explanation:

It is given that a sound wave travels through iron at a rate of 5120 m/s.

We know that

1 km = 1000 m

1 hour = 60 minutes

1 minutes = 60 second

Using these conversions we get

1 m = 0.001 km

1 hour  = 3600 second

5120\text{ m/s }=5120\times 0.001\times 3600\text{ km/h}

5120\text{ m/s }=18432\text{ km/h}

Therefore, the sound wave travels through iron at a rate of 18432 km/h.

6 0
3 years ago
You are given a problem that involves multiplying a positive number and a negative number.
kenny6666 [7]

Answer:

-3 and -2

Step-by-step explanation:

A better explanation...

(positive)(positive)= positive

(positive)(negative)= negative

(negative)(negative)= positive

(negative)(positive)= negative

3 0
3 years ago
Read 2 more answers
The grocery store sells kumquats for $4.75 a pound and Asian pears for $3.75 a pound. Write an equation in standard form for the
maks197457 [2]
<span>to find the solution to this problem, we must understand that the sum of the amount that the customer could be bought is $12. $4.75 pound of kumquats and Asian pears for $3.75 mean mathematically as $12. $4.75 kumquats + $3.75 Asian, this last sum is equal to $12, so the true answer is the choice B: 4.75k + 3.75p = 12 Hope this helps. Let me know if you need additional help!</span>
6 0
3 years ago
How do I prove that a quadrilateral is a rectangle? (in a Column chart with statement and reason)
klasskru [66]
By definition, we have to:

 In plane geometry, a rectangle is a parallelogram whose four sides are at right angles to each other. Opposite sides have the same length.

 There is a proof that a quadrilateral is a rectangle:

  1) Its parallel sides are the same.

 2) Its two diagonals are the same, and they bisect each other at the common midpoint

 3) Any rectangle can be inscribed in a circle, two of whose diameters coincide with the diagonals of the rectangle.

 4) If all the angles of a quadrilateral are right angles, then it is a rectangle
7 0
3 years ago
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