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olga2289 [7]
3 years ago
15

Answer this Question

Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

n = -13

Step-by-step explanation:

√10 - 3n = 7 ⇔

⇔ 10 - 3n = 49 ⇔ We need to remove the square root. Ex: √n = 2 ⇔ n = 2²

⇔  -3n = 49 - 10 ⇔
⇔ -3n = 39 ⇔
⇔ n = \frac{39}{-3} = -13 (as -3 changes members, as it was multiplying, it now divides, conversion).

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(a+b)2 ;a=1/2 and b=2
FrozenT [24]

Answer:

\frac{25}{4}

Step-by-step explanation:

a + b = \frac{1}{2} + 2 = 2 \frac{1}{2} = \frac{5}{2}, thus

(a + b)² = (\frac{5}{2} )² = \frac{5}{2} × \frac{5}{2} = \frac{5(5)}{2(2)} = \frac{25}{4}

8 0
3 years ago
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The square ABCD is divided into eight equal parts. The shaded area is 25 cm². What is the area of the square ABCD​
Akimi4 [234]

Answer:

I think the answer is 200cm^2

Step-by-step explanation:

since the square is divided into eight equal parts

and one shaded part is =25cm^2

multiply the area of the shaded part by the number of equal parts

= 25cm^2 ×8

= 200cm^2

6 0
3 years ago
Find the missing value of the sides.
umka2103 [35]

Answer:

The values for both of the missing sides is 8.

Step-by-step explanation:

The hypotenuse of a right triangle = a(square root of 2)

Therefore the other two missing sides equal a.

Therefore, the other two sides equal 8.

7 0
3 years ago
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Write the expression 3∙3∙3∙3∙3 in exponential form.<br><br><br> Evaluate the expression.<br> -62
kakasveta [241]

Answer:

3 to the power of 5 (I cant write as exponent)

Step-by-step explanation:

8 0
4 years ago
Use the given zero to find the remaining zeros of each function f(x)=2x^4+5x^3+5x^2+20x-12 zero:-2i
frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

  1. The Fundamental Theorem of Algebra tells us that any polynomial has <em>as many zeroes as its degree</em>. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
  2. Complex zeroes come in pairs. Specifically, they come in <em>conjugate pairs</em>. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both x-2i and x+2i are factors of f(x), and furthermore, their product, x^2+4, is <em>also</em> a factor. To see what's left after we factor out that product, we can use polynomial long division to find that

2x^4+5x^3+5x^2+20x-12=(x^2+4)(2x^2+5x-3)

I'll go through to steps to factor that second expression below:

2x^2+5x-3=2x^2+6x-x-3\\=2x(x+3)-(x+3)\\=(2x-1)(x+3)

Solving both of the expressions when f(x) = 0 gets us our final two zeroes:

2x-1=0\\2x=1\\x=1/2

x+3=0\\x=-3

So, the remaining zeroes are 1/2 and 3.

8 0
4 years ago
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