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crimeas [40]
3 years ago
9

Myrtle has a credit card that uses the average daily balance method. For the first 21 days of one of her billing cycles, her bal

ance was $2030, and for the last 9 days of the billing cycle, her balance was $1450. If her credit card's APR is 23%, which of these expressions could be used to calculate the amount Myrtle was charged in interest for the billing cycle?
(a)- (0.23/365 x30)÷(21x $2030+ 9x$1450/30)
(b)- (0.23/365 x30)÷(9x $2030+ 21x$1450/30)
(c)- (0.23/365 x31)÷(9x $2030+ 21x$1450/31)
(d)- (0.23/365 x31)÷(21x $2030+ 9x$1450/31)

Mathematics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

Step-by-step explanation:

levacccp [35]3 years ago
5 0

Answer:

A

I had this question yesterday

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Gala2k [10]

Answer:

b=60

Step-by-step explanation:

6+4/5b=9/10b

  -4/5b  -4/5b

6=1/10b

divide both sides by 1/10

b=60

5 0
3 years ago
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A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
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For what values of X are the statements below true
Galina-37 [17]

Answer:

See solutions below

Step-by-step explanation:

For what values of X are the statements below true

A. 1x>x+1

x >x+1

x-x>1

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B) |1-x|>3

The fucntion can both be positive and negative

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c) For the equation

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3/4. triangle FHE and triangle KMN; triangle GEH and triangle LNM
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48w + 42x. Write you're answere as a product with a whole number greater than 1???
Natali [406]

Answer:

6(8w + 7x)

Step-by-step explanation:

Hello!

The greatest common factor between 48 and 42 is 6. We can factor out 6 from each term.

<h3>Factor</h3>
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The expression is 6(8w + 7x).

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