Solve for x.<br> -2-2x/3=-8<br> = [?]

Sam's car traveled 120 miles on 9 gallons of gasoline. Which fraction expresses the ratio of miles to gallons?

gogolik [260]

Miles to gallons=120:9=40:3

6 0

3 years ago

I need help with number 9

nalin [4]

4y = - 2x + 12
y = - 2/4x + 3

The y intercept is 3

3 0

4 years ago

DUE VERY SOON URGENT PLEASE HELP!!

Alla [95]

The values of x are

1. x = 32°,

2. x = 15°,

3. x = 49°,

4. x = 65°,

Explanation:

The angle made by any right angle is 90° and the angle made by a straight line is 180°. These are the main equations required to solve the values of x. The first 2 are right angles and the last 2 are straight lines. So the sum of the components within that right angle is 90° and for a straight line is 180°.

For diagram 1; 2x° + x° - 6° = 90°, 3x° = 90° + 6° = 96°, x = $\frac{96}{3}$ = 32°.

For diagram 2; 4x° + 3° + x° + 12° = 90°, 5x° = 90° - 15° = 75°, x = $\frac{75}{5}$ = 15°.

For diagram 3; x° + 33° + 2x° = 180°, 3x° = 180° - 33 = 147°, x = $\frac{147}{3}$ = 49°.

For diagram 4; 2x° + 1° + x° - 16° = 180°, 3x° = 180° + 15° = 195°, x = $\frac{195}{3}$ = 65°.

7 0

3 years ago

Please help math asap 30 points

Bas_tet [7]

The answer is A

(5,3)

4 0

3 years ago

Read 2 more answers

A survey organization has used the methods of our class to construct an approximate 95% confidence interval for the mean annual

lawyer [7]

Answer:

$\bar X = \frac{66000+70000}{2}= 68000$

We can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000$

And the margin of error is given by:

$ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can rewrite the margin of error like this:

$ME =z_{\alpha/2}*SE$

Where $SE= \frac{\sigma}{\sqrt{n}}$

For 95% of confidence the critical value is $z_{\alpha/2}= \pm 1.96$

The Standard error would be:

$SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408$

For 99% of confidence the critical value is $z_{\alpha/2}= \pm 2.58$

And the new margin of error would be:

$ME = 2.58* 1020.408 = 2632.653$

And then the interval would be given by:

$Lower = 68000- 2632.653 = 65367.347$

$Upper = 68000+ 2632.653 = 70632.653$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The 95% confidence interval is given by (66000 , 70000)

We can estimate the mean with this formula:

$\bar X = \frac{66000+70000}{2}= 68000$

We can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000$

And the margin of error is given by:

$ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can rewrite the margin of error like this:

$ME =z_{\alpha/2}*SE$

Where $SE= \frac{\sigma}{\sqrt{n}}$

For 95% of confidence the critical value is $z_{\alpha/2}= \pm 1.96$

The Standard error would be:

$SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408$

For 99% of confidence the critical value is $z_{\alpha/2}= \pm 2.58$

And the new margin of error would be:

$ME = 2.58* 1020.408 = 2632.653$

And then the interval would be given by:

$Lower = 68000- 2632.653 = 65367.347$

$Upper = 68000+ 2632.653 = 70632.653$

7 0

4 years ago

Solve for x. -2-2x/3=-8 = [?]