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riadik2000 [5.3K]
2 years ago
11

Gwen has $30 in a savings account that earns 10% interest, compounded annually.

Mathematics
1 answer:
Ivanshal [37]2 years ago
8 0

Answer:

$36

Step-by-step explanation:

Hope I helped

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Find the value of x. Round to the nearest degree.
kari74 [83]

Answer: x = 33 degrees

Step-by-step explanation:

The given triangle is a right angle triangle.

From the given right angle triangle,

The length of the hypotenuse of the right angle triangle is 19

With x degrees as the reference angle,

The length of the adjacent side of the right angle triangle is 16

To determine x, we would apply trigonometric ratio

Cos θ = adjacent side/hypotenuse side. Therefore,

Cos x = 16/19 = 0.842

x = Cos^-1(0.842)

x = 33 degrees

6 0
4 years ago
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Which of the following appears to be a right isosceles triangle?
tigry1 [53]
Isosceles triangle= 2 concurrent sides
Right angle= 90°

So which one has two concurrent sides and a right angle? A. The right angle is marked as well as the sides.

C has 2 concurrent sides, but it's not marked as a right angle. Option B has neither of these.
7 0
3 years ago
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154=−4(8+6r) + 24r thanks to anyone who helps
vova2212 [387]

Answer:

When you do the math, you get an incorrect equation.

Step-by-step explanation:

154 = -32 -24r +24r

154 = -32

so you would get 186 = 0

4 0
2 years ago
The rate at which a professional tennis player used carbohydrates during a strenuous workout was found to be 1.7 grams per minut
Alex787 [66]

Answer:

<em>m=1.7</em>

<em>C=68 gr</em>

Step-by-step explanation:

<u>Function Modeling</u>

We are given a relationship between the carbohydrates used by a professional tennis player during a strenuous workout and the time in minutes as 1.7 grams per minute. Being C the carbohydrates in grams and t the time in minutes, the model is

C=1.7t

The slope m of the line is the coefficient of the independent variable, thus m=1.7

The graph of C vs t is shown in the image below.

To find how many carbohydrates the athlete would use in t=40 min, we plug in the value into the equation

C=1.7\cdot 40=68\ gr

8 0
3 years ago
In Bluepoint, the average low temperature for January was 40 °F. The average low in February was 27% lower. What was the average
yarga [219]

The average low temperature for January was 40 °F - 100%.

The average low in February was x °F - 27% lower, that is 100%-27%=73%.

Write a proportion:

\dfrac{40}{x}=\dfrac{100}{73},\\ \\x=\dfrac{73\cdot 40}{100},\\\\x=29.2

Answer: the average low in February was 29.2 °F.

5 0
3 years ago
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