The slope is 1/2 and the Y intercept is -3, so the equation will be Y=1/2x-3
In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66.What
Lunna [17]
Answer:
We conclude that the lower limit of a box-and-whiskers display is 65.
We conclude that the upper limit of a box-and-whiskers display is 77.
Step-by-step explanation:
Definition: A box-and-whisker plot or boxplot is a diagram based on the five-number summarytext annotation indicator of a data set.
In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66.
We conclude that the lower limit of a box-and-whiskers display is 65.
We conclude that the upper limit of a box-and-whiskers display is 77.
Answer:
18 hours
Step-by-step explanation:
First, he worked 3 hours babysitting, so he already made 8*3=24 dollars.
This means he must work 200-24=176 dollars lifeguarding.
Divide that by how much he makes per hour, and 176/15=11.7333 hours lifeguarding.
Round that up if he can't do a fraction of an hour to get 12 hours lifeguarding.
This is possible because the total hours worked is 12+3=15, which is less than 18.
Answer:
use the thingy with the holes I guess
We have been given that the average age of a breed of dog is 19.4 years. The distribution of their ages is normal and 20% of dogs are older than 22.8 years. We are asked to find the standard deviation.
Since 20% of dogs are older than 22.8 years, so 80% of dogs are younger than 22.8.
We will use z-score formula to solve our given problem.
, where,
z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Now we will use normal distribution table to find the z-score corresponding to 80% or 
.
z-score corresponding to 0.80 is 0.845.
Upon substituting our given values in z-score formula, we will get:
Therefore, the standard deviation is approximately 4.02 years.
