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anastassius [24]

2 years ago

9

Suppose you are asked to find the area of a figure in a specific unit of measure, but its side lengths are measured in a differe

nt. What must you do first?

1 answer:

UkoKoshka [18]2 years ago

3 0

Step-by-step explanation:

change the unite to the same one so that they can have the same unite

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in a classroom training student has to create a triangle pyramid using various items. Each group then used measurement to determ

balandron [24]

The formula for the volume of pyramid is,

$V=\frac{Bh}{3}$

Here, B is base area and height of pyramid.

The volume expression for group 4 is,

$V=\frac{1}{3}\cdot(\frac{8\cdot4}{2})\cdot9$

Here, expression,

$\frac{8\cdot4}{2}$

represents the base area and 9 represent the height of pyramid.

So height of the pyramid created by group 4 is 9.

Answer: 9

3 0

7 months ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

B

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

C

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

D

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

E

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

11 months ago

A researcher is planning to compare the effects of two different types of lights on the growth of bean plants. She expects that

kicyunya [14]

Answer:

The sample size is $n = 36$

Step-by-step explanation:

From the question we are told that

The sample standard deviation is $s = 1.5$

The mean difference of the two groups is $\=x _ 1 - \=x_2 = 1$

The standard error is $SE = \frac{ \= x_1 - \= x_2}{4}$

=> $SE = \frac{1}{4}$

Let assume that the confidence level is 95% hence the level of significance is

$\alpha = (100-95)\%$

=> $\alpha = 0.05$

So the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.96 * \frac{1}{4}$

$E = 0.49$

Generally the sample size is mathematically represented as

$n =[ \frac{Z_{\frac{\alpha }{2} * s^2}}{E}]^2$

=> $n = [\frac{1.96 * 1.5}{0.49} ]^2$

=> $n = 36$

6 0

2 years ago

1. Ellie has 2/8 pound of cheese. She used 1/2 of the cheese to make tacos. Since there are 16 ounces in one pound, how many oun

otez555 [7]

The ounces of cheese Ellie uses to make tacos is 2

What is a unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Calculation :

1 pound = 16 ounces

Total cheese Ellie has = $\frac{2}{8}$ pound

Cheese required to make tacos = $\frac{2}{8}$ × $\frac{1}{2}$ = $\frac{1}{8}$ pounds

Ounces of cheese required to make cheese are $\frac{1}{8}$ × 16 = 2 ounces

learn more about the unitary method here :

brainly.com/question/17110989

#SPJ1

8 0

1 year ago

Find m∠XYW and m∠WYZ m

makvit [3.9K]

Answer:

<XYZ = 117°

<XYW+ WYZ = 117°

(6x+44)+(-10x+65)= 117°

6x+44-10x+65= 117°

-4x+ 109= 117°

-4x= 117-109

-4x= 8

x= 8/-4

x= -2

<XYW= 6x+44= 6×-2+44= -12+44= 32°

<WYZ= -10x+65 = -10×-2+ 65= 20+65= 85°

Step-by-step explanation:

7 0

2 years ago