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anastassius [24]
3 years ago
9

Suppose you are asked to find the area of a figure in a specific unit of measure, but its side lengths are measured in a differe

nt. What must you do first?
Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0

Step-by-step explanation:

change the unite to the same one so that they can have the same unite

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A can of chili has a radius of 5.25 cm and a height of 13 cm. find the volume
spayn [35]

Answer:

1125.67

Step-by-step explanation:

4 0
3 years ago
For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

3 0
3 years ago
The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,
juin [17]

Answer:

The width is: w(x)=4x^2

The length is l(x)=2x^2+3x+5

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

a(x)=8x^5+12x^3+20x^2

The width of the rectangle is the greatest common factor of 8x^5,  12x^3 and 20x^2

That is the width is: w(x)=4x^2

We now divide the area by the width to obtain the length of the rectangle:

l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}

This simplifies to:

l(x)=\frac{8x^5}{4x^2}+\frac{12x^3}{4x^2}+\frac{20x^2}{4x^2}

l(x)=2x^2+3x+5

5 0
3 years ago
Read 2 more answers
Please help me with these two questions
melisa1 [442]

Hi! It will be a pleasure to help you finding the solution to this problem, so let's solve each part:

<h2>PART 1.</h2><h3>Finding the correct expression.</h3><h3>Correct answer:</h3>

\boxed{A. \ 1.50h+4}

From the problem, we know the following data of the problem:

  • Laval parked at the beach.
  • Laval paid a fixed price of $4 for a pass.
  • Laval paid $1.50 for each hour.

Our goal is to find the the expression for the total cost for parking at the beach for h hours. So:

Step 1: Since we have a fixed price, this value will appear in our expression:

4

Step 2: Since Laval paid $1.50 for each hour, this can be represented as the following expression:

1.50h

Finally, we can write total cost (C) as the sum of these two expressions:

C=1.50h+4

Finally, our correct option is A:

\boxed{1.50h+4}

<h2>PART 2.</h2><h3>Finding h.</h3><h3>Correct answer:</h3>

5 hours

Here we have to find how many hours Laval spent at the beach knowing that he paid a total amount of $11.50. From the previous part, we know that our expression is:

C=1.50h+4 \\ \\ For \ C=11.50 \\ \\ 11.50=1.50h+4 \\ \\ Subtracting \ 4 \ from \ both \ sides: \\ \\ 11.50-4=1.50h+4-4 \\ \\ 7.5=1.50h \\ \\ Dividing \ both \ sides \ by \ 1.50 \\ \\ h=\frac{7.5}{1.50}=5

Finally, he spent 5 hours at the beach

6 0
3 years ago
What would $1260 times 3.5% look like on paper as a math problem?
iren [92.7K]
$1260 * .035 = $44.10
3 0
3 years ago
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