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Molodets [167]
2 years ago
11

Alex is planning his birthday party. He needs 2 gallons of juice for every 15 guests. If Alex expecting 30 guests, how many gall

ons of juice are required? Round up the answer.
4 gallons

17 gallons

13 gallons

8 gallons
Mathematics
2 answers:
Sedbober [7]2 years ago
7 0

Answer:

4 gallons of juice are required

Step-by-step explanation:

He needs 2 gallons of juice for 15 guests.

He is expecting double the guests, so he need double gallons of juice.

2 gallons * 2 = 4 gallons

V125BC [204]2 years ago
4 0

Answer:

4 gallons. 2 gallons of juice for every 15 guests would mean that for the first 15 people that show up would be 2 gallons of juice, for the second 15 people so show up would be another 2 gallons. 2+2 is 4. 15+15 is 30.

Step-by-step explanation:

The answer would be a. 4 gallons

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3 years ago
Please explain how you got the answer.
photoshop1234 [79]

Answer:

Step-by-step explanation:

First, simplify the equation they give you

125x+200≥1200 ---------> 125x≥1000---------->x≥8

So, x has to be greater than or equal to 8 which rules out b or d.

So the answers are narrowed down to a and c, the only difference is that the dot in A is filled in whereas the dot in c is not. In math, having a filled in circle means that value is included (≥ sign), so we will choose the answer a.

8 0
2 years ago
Read 2 more answers
A scrap metal dealer claims that the mean of his sales is "no more than $80," but an Internal Revenue Service agent believes the
Artyom0805 [142]

Answer:

There is enough not evident to support dealer's claim that his sales is no more than $80.                              

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = $80

Sample mean, \bar{x} = $91

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = $21

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 80\text{ dollars}\\H_A: \mu > 80\text{ dollard}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{91 - 80}{\frac{21}{\sqrt{20}} } = 2.3425

Now, t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = 1.729

Since,                        

The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

There is enough not evident to support dealer's claim that his sales is no more than $80.

4 0
3 years ago
The total length of wires A, B, and C is 445 cm. Wire A is 45 cm longer than wire B, and wire B is half as long as wire C. How l
drek231 [11]

Answer:

<h2>A = 145 cm</h2><h2 />

Step-by-step explanation:

total length = 445 cm (A + B + C)

A = 45 + B

B = C/2

find A

A + B + C = AC

(45 + B) + (C/2) + C = 445

45 + C/2 + C/2 + C = 445

2C = 445 - 45

C = 400/2

C = 200

B = 200/2

B = 100

A = 45 + 100

A = 145

proof:

445 =  145 + 100 + 200

445 = 445 ----OK

3 0
3 years ago
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