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DochEvi [55]
2 years ago
12

ced tea. How do you make a larger batch of this mixture? Describe your procedure and use the table below to organize your result

s. Add more columns to the table if needed​
Mathematics
1 answer:
puteri [66]2 years ago
5 0

Answer:

whats the question ?

Step-by-step explanation:

explain pls

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A football team gained 5 yards, lost 8 yards, lost another 2 yards, and then gained 45 yards. What were the total yards gained o
Fudgin [204]

Answer:

yes you would be correct if they started with zero yards at the beginning

Step-by-step explanation:

6 0
3 years ago
Write the percent shown by each model. Explain your reasoning.
Sphinxa [80]
A) 1/3=33 1/3%
B) 2/3=66 2/3%
C) 1/6=16 2/3%

A) YOU CAN TURN THE FRACTION 1/3 INTO A DECIMAL WHICH WILL BE AROUND 0.333. THEN YOU TURN THE DECIMAL INTO A PERCENT. YOU CAN MOVE THE DECIMAL TWO PLACES TO THE RIGHT. THAT GIVES YOU 33.3% OR 33 1/3% THIS ALSO APPLIES TO B BUT WITH 0.666 AND 66.6%

FOR C, YOU DO THE SAME. 1/6 AS A DECIMAL IS 1.666. YOU MOVE THE DECIMAL TWO PLACES TO THE RIGHT. 16.6% OR 16 2/3%


HOPE THIS HELPED.
8 0
3 years ago
[09.02]
VLD [36.1K]

Answer:

4

Step-by-step explanation:

i took the test and got it right

7 0
3 years ago
Read 2 more answers
you are riding your bike and notice the square sign above. You mentally draw a straight line from point A to C. Describe the ang
inysia [295]

Answer:

They are both equal obtuse angles


7 0
3 years ago
A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weig
jenyasd209 [6]

Answer:

z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625    

The p value for this case would be given by:

p_v =P(z  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

Step-by-step explanation:

Information provided

\bar X=19.87 represent the sample mean

\sigma=0.4 represent the population deviation

n=25 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the info given we got:

z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625    

The p value for this case would be given by:

p_v =P(z  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

7 0
3 years ago
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