Answer:
This function is an even-degree polynomial, so the ends go off in the same directions, just like every quadratic I've ever graphed. Since the leading coefficient of this even-degree polynomial is positive, the ends came in and left out the top of the picture, just like every positive quadratic you've ever graphed. All even-degree polynomials behave, on their ends, like quadratics.
Step-by-step explanation:
Answer:
Factoring
Step-by-step explanation:
Answer: A is -8
Step-by-step explanation:
-6 times 6 = -36 then you would do -6 times -a = 6a then you would have
-36 + 6a = -84 then you would add 36 to both sides to get -48 then you would divided -48 by 6 to get -8
Step 1: Trying to factor as a Difference of Squares:
Factoring: x²⁰⁰² - 1
Theory : A difference of two perfect squares, A² - B² can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A² - AB + BA - B² =
A² - AB + AB - B²
A² - B²
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check: x²⁰⁰² is the square of x¹⁰⁰¹
Factorization is : (x¹⁰⁰¹ + 1) × (x¹⁰⁰¹ - 1)
Answer: Hello your question is incomplete below is the missing part
Which of the following statements about Hannah’s claim is supported by the interval?
A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.
B) Hannah is likely to be incorrect because 9 is not contained in the interval.
C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.
D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.
E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.
Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )
Step-by-step explanation:
The statement that is supported by the interval in Hannah's claim is that
Hannah is likely to be incorrect because 9 is not contained in the interval.
