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Blababa [14]
2 years ago
7

State if the two triangles are congruent. If they are, state how you know.

Mathematics
1 answer:
Elodia [21]2 years ago
4 0
17. Yes!! SAS theorem
18. Yes !! SSS theorem
19. Yes !! SSS theorem
20. I don’t think so
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Zeke had 9 dvds. His mother bought d more DVD. Write an expression that shows how many dvds zeke has now
Kitty [74]

Answer: 9+d=x or x=9+d

d-the new dvds

x-the unknown total

9-the dvds Zeke owned before

6 0
3 years ago
Verify that the points are the vertices of a parallelogram and find its area. (2,-1,1), (5, 1,4), (0,1,1), (3,3,4)
Gelneren [198K]

Answer:

Area = 13.15 square units

Step-by-step explanation:

Let the given vertices be represented as follows:

A(2, -1, 1) = 2i - j + k

B(5, 1, 4) = 5i + j + 4k

C(0, 1, 1) = 0i + j + k

D(3, 3, 4) = 3i + 3j + 4k

(i) Let's calculate the vectors of all the sides:

\\AB = B - A =  (5i + j + 4k) - (2i - j + k)

AB = 5i + j + 4k - 2i + j - k                 [Collect like terms]

AB = 3i + 2j + 3k

BC = C - B =  (0i + j + k) - (5i + j + 4k)

BC = 0i + j + k - 5i - j - 4k                 [Collect like terms]

BC = -5i + 0j - 3k

CD = D - C =  (3i + 3j + 4k) - (0i + j + k)

CD = 3i + 3j + 4k - 0i - j - k                [Collect like terms]

CD = 3i + 2j + 3k

DA = A - D =  (2i - j + k) - (3i + 3j + 4k)

DA = 2i - j + k - 3i - 3j - 4k                [Collect like terms]

DA = -i - 4j - 3k

AC = C - A =  (0i + j + k) - (2i - j + k)

AC = 0i + j + k - 2i + j - k                [Collect like terms]

AC = -2i + 2j

BD = D - B = (3i + 3j + 4k) - (5i + j + 4k)

BD = 3i + 3j + 4k - 5i - j - 4k                [Collect like terms]

BD = -2i + 2j

(ii) From the results in (i) above, we can deduce that;

AB = CD This implies that AB || CD  [AB is parallel to CD]

AC = BD This implies that AC || BD  [AC is parallel to BD]

(iii) Therefore, ABDC is a parallelogram since opposite sides (AB and CD) are parallel. Hence, the points are vertices of a parallelogram

<u>Now let's calculate the area</u>

To find the area of the parallelogram, we find the magnitude of the cross product of any two adjacent sides.

In this case, we'll choose AB and AC

Area = |AB X AC|

Where;

AB X AC = \left[\begin{array}{ccc}i&j&k\\3&2&3\\-2&2&0\end{array}\right]

<u></u>

AB X AC = i(0 - 6) - j(0 + 6) + k(6 + 4)

AB X AC = - 6i - 6j + 10k

|AB X AC| = \sqrt{(-6)^2 + (-6)^2 + (10)^2}

|AB X AC| = \sqrt{172}

|AB X AC| = 13.15

Area = 13.15 square units.

<u></u>

<u></u>

<u>PS: </u> ACBD is also a parallelogram. The diagram has also been attached to this response.

6 0
3 years ago
Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0
Deffense [45]
\bf sin(x)cos(x)=0\implies &#10;\begin{cases}&#10;sin(x)=0\\&#10;\measuredangle x=sin^{-1}(0)\\&#10;\measuredangle x=0\ ,\ \pi \\&#10;----------\\&#10;cos(x)=0\\&#10;\measuredangle x=cos^{-1}(0)\\&#10;\measuredangle x=\frac{\pi }{2}\ ,\ \frac{3\pi }{2}&#10;\end{cases}
3 0
3 years ago
Read 2 more answers
How do I find the slope of the line through (–9, –10) and (–2, –5)?
storchak [24]
Answer:
slope of line is 5/7

Explanation:
The slope of the line can be calculated using the following rule:
slope = \frac{y2-y1}{x2-x1}

The given points are:
(-9,-10) which represent (x1,y1)
(-2,-5) which represent (x2,y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-5-(-10)}{-2-(-9)} = 5/7

Hope this helps :)

4 0
4 years ago
Read 2 more answers
-2 1/3 × 2 5/8 Perform the indicated operation
Karolina [17]

Answer:

-6 1/8

Step-by-step explanation:

=-7/3 *21/8

=147/24

=-6 3/24

=-6 1/8

8 0
4 years ago
Read 2 more answers
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