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3 years ago

I need you to help me solve this

Mathematics

1 answer:

Svet_ta [14]3 years ago

7 0

For the expression to be factor-able the Discriminant , has to be greater or equal to zero
ax^2 + cx + b = 0

c^2 - 4 ab >= 0

(-3)^2 - 4 * 1 * b >= 0

9 - 4b >= 0

9 >= 4b

b <= 9/4 (2.25)

Pick any value in that range for ex:

0 , 2, -3, -6

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Expand the expression and combine like terms.(2+2w)⋅4+9(w+3)

Nonamiya [84]

0.8+0.8w+9w+27
9.8w+27.8

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3 years ago

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Answer:

4.9*6.7 = 32.83

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2 years ago

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Luisa and Connor had $360 altogether . After Connor gave Luisa 2/5 of his money, she had the same amount of money has he did. Ho

Liula [17]

Answer:

$300

Step-by-step explanation:

Let's say that L is the amount of money Luisa had in the beginning, and C is the amount of money Connor had in the beginning.

C + L = 360

C - 2/5 C = L + 2/5 C

Simplifying the second equation:

3/5 C = L + 2/5 C

1/5 C = L

Substituting into the first equation:

C + 1/5 C = 360

6/5 C = 360

C = 300

Connor originally had $300, and Luisa $60. Connor gave Luisa $120, and they both had $180.

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3 years ago

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Paha777 [63]

Answer:

81 square metres is right anser follow me plse

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2 years ago

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Is the sequence geometric? if so, identify the common ratio 1/5,2/15,4/45,8/135,16/405,...

Romashka-Z-Leto [24]

So have the sequence: $\frac{1}{5} , \frac{2}{15} , \frac{4}{45} , \frac{8}{135} , \frac{16}{145} ,...$
To check if the sequence is geometric, we are going to find its common ratio; to do it we are going to use the formula: $r= \frac{a_{n} }{a_{n-1}}$
where
$r$ is the common ratio
$a_{n}$ is the current term in the sequence
$a_{n-1}$ is the previous term in the sequence
In other words we are going to divide the current term by the previous term a few times, and we will to check if that ratio is the same:

For $a_{n}= \frac{2}{15}$ and $a_{n-1}= \frac{1}{5}$ :
$r= \frac{ \frac{2}{15} }{ \frac{1}{5} }$
$r= \frac{2}{3}$

For $a_{n}= \frac{4}{45}$ and $a_{n-1}= \frac{2}{15}$ :
$r= \frac{ \frac{4}{45} }{ \frac{2}{15} }$
$r= \frac{2}{3}$

For $a_{n}= \frac{8}{135}$ and $a_{n-1}= \frac{4}{45}$ :
$r= \frac{ \frac{8}{135} }{ \frac{4}{45} }$
$r= \frac{2}{3}$
As you can see, we have a common ratio!

We can conclude that our sequence is a geometric sequence and its common ratio is $\frac{2}{3}$

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3 years ago

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