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gogolik [260]
3 years ago
10

I need you to help me solve this

Mathematics
1 answer:
Svet_ta [14]3 years ago
7 0
For the expression to be factor-able the Discriminant  , has to be greater or equal to zero
ax^2 + cx + b = 0


c^2 - 4 ab >= 0 

(-3)^2 - 4 * 1 * b >= 0

9 - 4b >= 0

9 >= 4b

b <= 9/4  (2.25)

Pick any value in that range for ex:

0 , 2,  -3, -6

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How can parallel lines be used to compare figures E and F? Explain your reasoning.
Aneli [31]

Answer:

The similarities are

1) The length of E and F can be described by two parallel lines spaced 3 blocks apart where the parallel line on the left of both E and F is 2 blocks long, while the parallel line on the right is one block long

2) Both height of E and F can be described by two parallel lines spaced 2 blocks apart  where the parallel line on the top of both E and F is 3 blocks long, while the parallel line at the bottom is one block long

3) The interior of E an F can be described by parallel lines 2 blocks long in the horizontal portion and one block long in the vertical portion

The differences are

1) The difference between E and F is that the parallel lines used for the construction of E are all one block higher than that of F

2) The other difference is that all the lines used for the construction of the figure E are 3 blocks to the left of those used for the construction of F

Figure F is essentially the translation of figure E three blocks to right and one block down

Step-by-step explanation:

3 0
3 years ago
It rained 12 days out of 30 days. Which
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3 0
2 years ago
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PtichkaEL [24]
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3 0
3 years ago
Read 2 more answers
Calculate the tenth term for n + 3<br> (n + 3)
rewona [7]

Answer:

10 + 3 = 13

Step-by-step explanation:

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3 0
2 years ago
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

probability=\frac{6 (6)}{270725}

probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
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