Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
<span>d)\sqrt(300-0.5p)..............................</span>
Answer:
a=4220-2t
This would be if we are finding the altitude of the submarine from the surface of the water(how many meters away from the surface it is). I don't know what it would be if you want to know from the bottom of the ocean.
The computation shows that the number of pages is 320.
The number of pages read in this second day will be 120.
<h3>How to illustrate the information?</h3>
Fraction read on first day = 1/4
Fraction news on second day = 1/2 × 3/4 = 3/8
Fraction read on last day = 1 - (1/4 + 3/8) =3/8
The number of pages that the book has will be:
= 3/8 × x = 120
0.375x = 120
x = 120/0.375
x = 320
The number of pages is 320.
b. The number of pages read on this second day will be:
= 3/8 × 320
= 120
Learn more about computations on:
brainly.com/question/4658834
#SPJ1
Answer:
42x^2 - 7x - 6x + 1
42x^2 - 13x + 1 for FOIL method
To solve for x
7x - 1 = 0
7x = 1
x = 1/7
6x - 1 = 0
6x = 1
x = 1/6
Step-by-step explanation:
