The answer is c,b,a. I’m pretty sure
Answer:
48/30 3/18 40/16 6/9 21/49 20/15 18/24 30/25 8/16
Step-by-step explanation:
Find the common denominator, then whatever it is, multiply the top to match it. For examples you start with 7/5 and you are trying to get the denominator to 25, you would multiply 7x5 which equals 35/25. Hope this helps.
Answer:
The weights of each cylinder and prism are 3 and 4 ounces, respectively.
Step-by-step explanation:
Let be 
and 
the masses of a cylinder and a prism, measured in ounces, respectively. After a careful reading of the statement we get the following linear equations by interpretation:
i) <em>She found that 4 cylinders and 5 prisms weigh 32 ounces:</em>
(Eq. 1)
ii) <em>And that 1 cylinder and 8 prisms weigh 35 ounces:</em>
(Eq. 2)
Now we solve the system of linear equations algebraically:
From (Eq. 2):
(Eq. 2) is (Eq. 1):
From (Eq. 2):
The weights of each cylinder and prism are 3 and 4 ounces, respectively.
The question given is incomplete, I googled and got the complete question as below:
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.
a. What is the probability that your last pot will have the necessary 7 crabs?
b. What is the probability that your last pot will be empty?
Answer:
a. Probability = 0.0083
b. Probability = 0.0907
Step-by-step explanation:
This is Poisson distribution with parameter λ=2.4
a)
The probability that your last pot will have the necessary 7 crabs is calculated below:
P(X=7)= {e-2.4*2.47/7!} = 0.0083
b)
The probability that your last pot will be empty is calculated as:
P(X=0)= {e-2.4*2.40/0!} = 0.0907
