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2 years ago

8

Jacob’s daily tips this work week were $99, $78, $58, $91, $90, and $68. Is Jacob correct in thinking that the median best repre

sents how much money he makes in daily tips?
No, Jacob is not correct. The mean amount he makes is $82.67 in a day.
Yes, Jacob is correct. The mean amount he makes is $81.67 in a day.
No, Jacob is not correct. The median amount he makes is $86.00 in a day.
Yes, Jacob is correct. The median amount he makes is $84.00 in a day.

2 answers:

NikAS [45]2 years ago

4 0

Answer:

the correct answer is D) Yes, Jacob is correct. The median amount he makes is $84.00 in a day.

Step-by-step explanation: just took the test.

Strike441 [17]2 years ago

4 0

Answer:

d

Step-by-step explanation:

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Pllllllllllllllllllllleasee one guys i neeed ur help one

Svetllana [295]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

Calculate discriminant :

$\qquad \sf \dashrightarrow \: 3 {x}^{2} + 6x - 1$

a = 3
b = 6
c = 1

$\qquad \sf \dashrightarrow \: discriminant = {b}^{2} - 4ac$

$\qquad \sf \dashrightarrow \: d = (6) {}^{2} - (4 \times 3 \times 1)$

$\qquad \sf \dashrightarrow \: d = 36 - 12$

$\qquad \sf \dashrightarrow \: d = 24$

$\qquad \sf \dashrightarrow \: \sqrt {d} = 2 \sqrt{6}$

Now, let's calculate it's roots ( x - intercepts )

$\qquad \sf \dashrightarrow \: x = \cfrac{ - b \pm \sqrt{d} }{2a}$

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{2 \times 3}$

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{6}$

So, the intercepts are :

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6 - 2 \sqrt{6} }{6}$

and

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6 + 2 \sqrt{6} }{6}$

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1 year ago

Read 2 more answers

Help help help help what is the answer −5(4x−3)−x+5=190!!!

artcher [175]

X=8.5
190-5=185
185/-5=-37
-37-3=-34
34/4=8.5

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2 years ago

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

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2 years ago

Find all solutions to each quadratic equation

romanna [79]

I hope this helps you

2x^2-4x+7=0 a=2 b=-4 c= 7

disctirminant =b^2-4ac

disctirminant =(-4)^2-4.2.7

disctirminant = 16-56= -40

x=-b+square root of disctirminant ÷2a

x=4+2square root of (-10)/4

x=2+square root of (-10)/2

x'=4 -2 square root of (-10)/4

x'=2 -square root of (-10)/2

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2 years ago

Need help with #9 please

zlopas [31]

The first, fourth and fifth ones are linear.

The second, third and sixth are all nonlinear.

You can tell this by the fact that their lead exponents are not 1.

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2 years ago