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1 year ago

Maria put 18 crayons in 3 different baskets. She put the same number of crayons in each basket

Mathematics

2 answers:

Paladinen [302]1 year ago

7 0

Answer:

there are 6 crayons in each basket.

Step-by-step explanation:

forsale [732]1 year ago

3 0

Answer:

54 or 6 I would go with the 54 but if she 18 crayons in 3 it would be that but if she split 18 in thirds and put them in the basket you should put 6 if its that.

Step-by-step explanation:

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A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

2 years ago

The radius of a circle is 6mm. What is the area of the shaded portion of the circle.

mariarad [96]

Answer:

b) 29π mm²

Step-by-step explanation:

$\frac{360}{360} - \frac{70}{360} = \frac{290}{360} \\ \\\pi \: {r}^{2} \\ = \frac{290}{360} \times \pi\times 6 \times 6 \\ = 29 \: \pi \: {mm}^{2}$

6 0

2 years ago

3x-50 (7x) find the value of x

Naya [18.7K]

x=23

Simplifying

(3x + -50) + (7x)

Reorder the terms:

(-50 + 3x) + (7x)

Remove parenthesis around (-50 + 3x)

-50 + 3x + (7x) =

Combine like terms: 3x + (7x)

-50 + 10x

Solving

-50 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.

-50 + 50 + 10x = 180 + 50

Combine like terms: -50 + 50 = 0

0 + 10x = 180 + 50

10x = 180 + 50

Combine like terms: 180 + 50 = 230

10x = 230

Divide each side by '10'.

Simplifying

x = 23

8 0

2 years ago

Meera and Ben saved some money. 3/5 of Meera’s money are twice the money of Ben’s. Whats the new rapport between them?

cestrela7 [59]

Answer:

David used 1/2 of apple juice for every 1/4 cup of cranberry juice to make a fruit drink

3 0

1 year ago

Select the correct answer. The volume of one of the Great Lakes is 3. 5 × 103 cubic kilometers. If there are 6. 3 × 107 fish in

valentinak56 [21]

The average number of fish per cubic kilometer is $1. 8 \times 10^4$ .

The correct option is B.

Given

The volume of one of the Great Lakes is 3.5 × 103 cubic kilometers.

The number of fish in the lake = 6. 3 × 107.

<h3>What is the average value?</h3>

The average is the middle value of the given data set and is calculated by adding up all the numbers and dividing the result by the total quantity of figures added.

The average number of fish per cubic kilometer is given by;

$\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}$

Substitute all the values in the formula;

$\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}\\\\ \text{The average number of fish per cubic kilometer}= \dfrac{6.3\times 10^7}{3.5\times 10^3}\\ \text{The average number of fish per cubic kilometer}= 1.8 \times 10^4$

Hence, the average number of fish per cubic kilometer is $1. 8 \times 10^4$ .

To know more about the Average rate click the link given below.

brainly.com/question/12395856

5 0

1 year ago