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Fynjy0 [20]
3 years ago
8

What is the error in the work?

Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

you cannot subtract 12x² from -14x they are not "like" terms

Step-by-step explanation:

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Given g(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%5E2%2B2x%7D" id="TexFormula1" title="\frac{3}{x^2+2x}" alt="\f
sweet [91]

We know that g(x) = \frac{3}{x^2+2x}

We have to find g^-1(x)  or inverse of g(x)

Inverse of g(x) can be determined by equating g(x) to y, and determining the value of x in terms of y

g(x) = y = \frac{3}{x^2+2x}

⇒ y × (x² + 2x) = 3

⇒ yx² + 2xy = 3

⇒ yx² + 2yx - 3 = 0

Determining the roots of x using:

x = \frac{-b + \sqrt{b^{2} - 4ac}}{2a} OR x = \frac{-b - \sqrt{b^{2} - 4ac}}{2a} , where a is coefficient of x², b is coefficient of x, and c is the constant

⇒ x = \frac{-2y + \sqrt{4y^2 - 4(2y)(-3)}}{2y} OR x = \frac{-2y - \sqrt{4y^2 - 4(2y)(-3)}}{2y}

⇒ x = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

Hence, g^-1(x) = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

7 0
3 years ago
Read 2 more answers
Simplify 21:9<br> Pls help me
Leno4ka [110]

Answer:

\frac{21}{9}  \\  \\  \frac{7}{3}  \\  \\

3 0
3 years ago
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