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Trava [24]
3 years ago
13

How do you solve question 43 and 44?

Mathematics
1 answer:
Sauron [17]3 years ago
5 0
<1=90=3y-6
3y=96
y=96:3
y=32
9x=6z=90
x=10
z=90:6
z=15

44. BD=AC
     2x-1+3y+5=4x-y+1
     2x+3y+4=4x-y+1
      3y+y+4-1=4x-2x
       4y+3=2x
       3y+5=2x-1
        3y+5=(4y+3)-1
         3y+5=4y+2
          5-2=4y-3y
          y=3
2x=4y+3=4*3+3=15
   x=15:2
x=7,5
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