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Trava [24]
3 years ago
13

How do you solve question 43 and 44?

Mathematics
1 answer:
Sauron [17]3 years ago
5 0
<1=90=3y-6
3y=96
y=96:3
y=32
9x=6z=90
x=10
z=90:6
z=15

44. BD=AC
     2x-1+3y+5=4x-y+1
     2x+3y+4=4x-y+1
      3y+y+4-1=4x-2x
       4y+3=2x
       3y+5=2x-1
        3y+5=(4y+3)-1
         3y+5=4y+2
          5-2=4y-3y
          y=3
2x=4y+3=4*3+3=15
   x=15:2
x=7,5
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g Given the following premises: (1) a∧(b∨a) (2) ~c→~a (3) ~g→~a (4) g→e (5)~(d∨h) Prove the Conclusion: c∧~h?
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Answer:

See the argument below

Step-by-step explanation:

I will give the argument in symbolic form, using rules of inference.

First, let's conclude c.

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¬(¬a)∧(2)⇒¬(¬c) by Modus tollens

¬(¬c)⇒c by double negation

Now, the premise (5) is equivalent to ¬d∧¬h which is one of De Morgan's laws. From simplification, we conclude ¬h. We also concluded c before, then by adjunction, we conclude c∧¬h.

An alternative approach to De Morgan's law is the following:

By contradiction proof, assume h is true.

h⇒d∨h by addition

(5)∧(d∨h)⇒¬(d∨h)∧(d∨h), a contradiction. Hence we conclude ¬h.    

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3 years ago
Decide whether or not it is possible for a triangle to have three angle measurements or three side lengths given. If it is possi
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Step-by-step explanation:

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