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2 years ago

How do you solve question 43 and 44?

Mathematics

1 answer:

Sauron [17]2 years ago

5 0

<1=90=3y-6
3y=96
y=96:3
y=32
9x=6z=90
x=10
z=90:6
z=15

44. BD=AC
2x-1+3y+5=4x-y+1
2x+3y+4=4x-y+1
3y+y+4-1=4x-2x
4y+3=2x
3y+5=2x-1
3y+5=(4y+3)-1
3y+5=4y+2
5-2=4y-3y
y=3
2x=4y+3=4*3+3=15
x=15:2
x=7,5

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