How do you solve question 43 and 44?

Mathematics

1 answer:

Sauron [17]3 years ago

5 0

<1=90=3y-6
3y=96
y=96:3
y=32
9x=6z=90
x=10
z=90:6
z=15

44. BD=AC
2x-1+3y+5=4x-y+1
2x+3y+4=4x-y+1
3y+y+4-1=4x-2x
4y+3=2x
3y+5=2x-1
3y+5=(4y+3)-1
3y+5=4y+2
5-2=4y-3y
y=3
2x=4y+3=4*3+3=15
x=15:2
x=7,5

You might be interested in

Can anyone help with the answers to all these questions with an explanation please?

saveliy_v [14]

ANSWER:

1) 25.70 cm 2) 30.84 cm 3) 10.71 km 4) 1.07 km 5) 6.71 cm 6) 10.07 mm

EXPLANATION:

1. Know that the circumference formula for a full circle is:

$C = 2\pi r$

The value of pi ( $\pi$ ) = 3.14

The radius ( $r$ ) will be given in the diagrams.

2. Now we can figure out the perimeters.

Shape One: Semi-circle

C = 2 x 3.14 x 5

C = 31.4 cm

Divide the circumference by 2 because it is a semi-circle. Then add 10 cm to this (because the flat side is 10 cm).

P = $\frac{31.4}{2} +10$

P = 25.7 cm ≈ 25.70 cm

Shape Two: Semi-circle

C = 2 x 3.14 x 6 (the picture shows the diameter so we need to half that to get the radius)

C = 37.68 cm

Divide the circumference by 2 because it is a semi-circle. Then add 12 cm to this (because the flat side is 12 cm).

P = $\frac{37.68}{2}+12$

P = 30.84 cm

Shape Three: Quadrant

C = 2 x 3.14 x 3

C = 18.84 km

Divide the circumference by 4 because it is a quadrant. Then add 6 km to this (because the two flat sides are 3 km each and so it is 6 km total).

P = $\frac{18.84}{4} +6$

P = 10.71 km

Shape Four: Quadrant

C = 2 x 3.14 x 0.3

C = 1.884 km

Divide the circumference by 4 because it is a quadrant. Then add 0.6 to this (because the two flat sides are 0.3 km each and so it is 0.6 km total).

P = $\frac{1.884}{4} + 0.6$

P = 1.071 km ≈ 1.07 km

Shape Five

C = 2 x 3.14 x 1

C = 6.28 cm

For this shape, we need to subtract the circumference of the missing sector from the circumference of the full circle to obtain the circumference for this shape. So, the circumference for the shape would be:

C = $6.28 - \frac{6.28}{4}$