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lukranit [14]
2 years ago
15

Smith can pick 115 strawberries in 5 minutes. How many strawberries can he pick per one minute?

Mathematics
1 answer:
defon2 years ago
6 0

Answer:

23

Step-by-step explanation:

1) to find the difference you hve to to divide the amount of strawberries by 5, to see how many he picked in 1 minute

Therefore: 115/5 = 23

Aka, Smith picked/ can pick 23 strawberries per minute :)

Have an amazing day!

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a trapezoide has an area of 150 square meters. If the bases are 14 meters and 16 meters, what is the height of the trapezoid​
SIZIF [17.4K]

Answer:

h = 10 m

Step-by-step explanation:

The formula for area of a trapezoid is  

A = (1/2)(B + b)h   where B is the bottom base, b is the top base, and h is the height.  

We are given B = 16, b = 14, and A = 15, plug those values in and simplify

150 = (1/2)(16 + 14)(h)

      150 = (1/2)(30)(h)

          150 = (15)h             (half of 30 is 15)

                10 m =  h       (divide both sides by 15 to isolate h)

6 0
4 years ago
Nick can read 3 pages in 1 minute. Write the ordered pairs (number of minutes, number of pages read) for Nick reading 0,1,2,and
Mariana [72]
Y = 3x....where y is # pgs read and x = # of minutes

0 minutes....x = 0
y = 3(0)
y = 0
ordered pair (0,0)

1 minute...x = 1
y = 3(1)
y = 3
ordered pair (1,3)

2 minutes...x = 2
y = 3(2)
y = 6
ordered pair (2,6)

3 minutes...x = 3
y = 3(3)
y = 9
ordered pair (3,9)
4 0
3 years ago
Which percent is equivalent to 1/20
solmaris [256]

Answer:

5%

Step-by-step explanation:

1/20 = 0.05

0.05 = 5%

3 0
3 years ago
Read 2 more answers
Four-fiths of a number minus two is greater then three-tenths of twice of that number
pashok25 [27]

Answer:

Step-by-step explanation:

4/5 x - 2 > 3/10 * 2x

4/5 x - 2 > 3/5 x

4/5 x - 2 - 3/5x> 0

1/5x > 2

x > 10

7 0
3 years ago
Given that the employed adult is male, what is the probability that he felt tense or stressed out at work
SVETLANKA909090 [29]
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out  during work were 244 and those that never felt stressed out were 495.
 Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B) 
P(B) is the probability of having a male.
 P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
   and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
                        = 244/739
                         =  0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
3 0
3 years ago
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