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2 years ago

Identify the vertex of the function f(x)=|x-1/2|-2

Mathematics

1 answer:

Assoli18 [71]2 years ago

7 0

Answer:

Step-by-step explanation:

vertex is (1/2,-2)

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The heights of american men aged 18 to 24 are approximately normally distributed with a mean of 68 inches and standard deviation

Rudik [331]

A normal distribution is symmetrical about the mean. Therefore half of all young men are shorter than 68 inches.

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3 years ago

Read 2 more answers

HURRY !!

LekaFEV [45]

Answer:

B. In step 2, marquis should have interpreted the results as x _< - 9.2, which means that x is less than or equal to -9.2

Step-by-step explanation:

Step 1 is correct.

Step 2.

-9.2 >= x

Subtract x from both sides.

-x - 9.2 >= 0

Add 9.2 to both sides.

-x >= 9.2

Divide both sides by -1. When you multiply or divide both sides of an inequality, the inequality sign changes direction.

x <= -9.2

The first error is in Step 2.

Answer:

B. In step 2, marquis should have interpreted the results as x _< - 9.2, which means that x is less than or equal to -9.2

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3 years ago

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The diagram shows the measurements of a frame into which concrete is poured to make steps. The steps are shaped like rectangular

Ivahew [28]

(6 x 16 x 6) + (14 x 16 x 7)
Answer = B

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3 years ago

12(x - 1) = - 4(3-X) + 8x

Dimas [21]

This equation has infinite solutions, any real number makes it true.

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2 years ago

Give an example of each of the following or explain why you think such a set could not exist.

Oksanka [162]

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

$(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi$

Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself

$(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi$

Interior point of set :Let $a\in S$ .Then a is called interior point of set when its neighborhood is a subset of set S.

$a\in(a-\epsilon,e+\epsilon)\subset S$

When a set is uncountable then interior point exist it is necessary for interior points existance .

Boundary points :Let $a\in S$ .If every non empty neighborhood of a intersect S and complement of S.

Every member of a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point

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3 years ago