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Goryan [66]
2 years ago
7

Two friends, Lucy and Lydia, had just bought their first cars. Lydia uses 3 gallons of gas to drive 114 miles in her car. The gr

aph below represents the number of miles, y that Lucy can drive her car for every gallons of gas. Lucy's Gas Mileage 00 850 600 FO 500 (10,415) NEXT SLIME DO (5,207 5) 13 Gallops of Gas How many miles less doen Lydia's car travel on one gallon of gas than Lucy's car?​

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

Answer:

3.5 miles

Step-by-step explanation:

Lydia:

3 gallons of gas = 114 miles

We want to know how many miles a friend can travel on one gallon of gas, so we divide both sides by 3

1 gallon of gas = 114/3 miles = 38 miles

Lucy:

One point is

10x corresponds to 415y

10 gallons = 415 miles

divide both sides by 10 to get one gallon on a side

1 gallon = 41.5 miles

Lydia:

38 miles = 1 gallon

Lucy:

41.5 miles = 1 gallon

For 1 gallon, the difference is 3.5 miles, with Lydia having 3.5 miles less than Lucy.

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On what date did Thomas jefferson submit the Declaration of Independence to peers for editing?
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Answer:

C. June 28, 1776

Step-by-step explanation:

Submitting the Declaration of Independence to the Continental Congress, June 28, 1776. This image is considered one of the most realistic renditions of this historical event.

7 0
4 years ago
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Factorize <br>m²-2mn+n²-9r​
san4es73 [151]

Answer:

(m-n)^{2}-9r

Step-by-step explanation:

m²-2mn+n²-9r​

(m-n)^{2}-9r

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3 years ago
Can someone help me with this question?
horsena [70]

Answer:

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Step-by-step explanation:

3 0
3 years ago
The cost is 284 the operating expenses are 43 the reduced price is 299 what is the operating loss
NISA [10]

Answer:

28

Step-by-step explanation:

operating loss is loss when value of operating loss is more than gross profit.

In the given problem

cost: 284

price : 299

profit = 299 - 284 = 15

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operating expenses = 43

as expense is greater than profit there is loss which is called operating loss.

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8 0
4 years ago
A recent kellogg survey shows that approximately 34% of americans eat breakfast. suppose alex takes a random sample of four amer
vlabodo [156]

This kind of experiments are ruled by Bernoulli's formula. If you have probability p of "success", and you want k successes in n trials, the probability is


\binom{n}{k}p^k(1-p)^{n-k}


It's easier to compute the first probability by difference: instead of computing the probability of the event "at least one of the surveyed eats breakfast", let's compute the probability of its contrary: none of them eats breakfast. So, we want 0 successes in 4 trials, with probability of success 0.34. The formula yields


\binom{4}{0} 0.34^0 0.64^4 = 0.64^4 \approx 0.17 = 17\%


Since the contrary has probability 17%, our event "at least one of the surveyed eats breakfast" has probability 83%.


As for the second question, the event "at least three of the surveyed eats breakfast" is the union of the events "exactly three of the surveyed eats breakfast" and "exactly four of the surveyed eats breakfast". So, we just need to sum their probabilities:


\binom{4}{3} 0.34^3 0.64^1 +\binom{4}{4} 0.34^4 0.64^0 = 4\cdot  0.34^3 0.64 + 0.34^4 \approx 0.11 = 11\%

3 0
3 years ago
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