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ValentinkaMS [17]
2 years ago
5

Which of the following is not a Pythagorean triple?

Mathematics
1 answer:
Ierofanga [76]2 years ago
8 0

Answer:

  (7, 24, 26)

Step-by-step explanation:

A Pythagorean triple must have an odd number of even numbers. The triple (7, 24, 26) is not a Pythagorean triple.

_____

<em>Additional comment</em>

For an odd integer n, a triple can be formed as ...

  (n, (n²-1)/2, (n²+1)/2)

That is, the following will be Pythagorean triples.

  • (3, 4, 5)
  • (5, 12, 13)
  • (7, 24, 25)
  • (9, 40, 41)
  • (11, 60, 61)

Another series involves even numbers and numbers separated by 2:

  (2n, n²-1, n²+1)

  • (8, 15, 17)
  • (12, 35, 37)
  • (16, 63, 65)

In this list, if n is not a multiple of 2, the triple will be a multiple of one from the odd-number series.

It is a good idea to remember a few of these, as they tend to show up in Algebra, Geometry, and Trigonometry problems.

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Your family goes to a Southern-style restaurant for dinner. There are 6 people in your family.
swat32

Answer:

We conclude that:

  • The number of people who ordered the chicken dinner = 1
  • The number of people who ordered the steak dinner = 5

Step-by-step explanation:

Given that

  • Some order the chicken dinner for $14
  • some order the steak dinner for $17.
  • Total bill = $99

  • Let 'n' be the number of people who ordered the chicken dinner.
  • Let '6-n' be the number of people who ordered the steak dinner.

Thus, the equation becomes

14n + 17(6-n) = 99

14n + 102 - 17n = 99

-3n = 99 - 102

-3n = -3

Divide both sides by -3

n = 1

and

6-n = 6-1 = 5

Therefore, we conclude that:

  • The number of people who ordered the chicken dinner = 1
  • The number of people who ordered the steak dinner = 5
7 0
3 years ago
Find the measurement of E<br> •56<br> •132<br> •51<br> •63
Burka [1]

Answer:

∠ E = 56°

Step-by-step explanation:

the external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ MGF is an exterior angle of the triangle , then

10x + 12 = 5x - 4 + 76

10x + 12 = 5x + 72 ( subtract 5x from both sides )

5x + 12 = 72 ( subtract 12 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

Then

∠ E = 5x - 4 = 5(12) - 4 = 60 - 4 = 56°

4 0
2 years ago
Read 2 more answers
Please Help. ------------------------------------------------------
Morgarella [4.7K]

Answer:

  positive integers less than or equal to 4

Step-by-step explanation:

The number of splits is described by a counting number: 1, 2, 3, ..., so is a positive integer. The description of the plant tells you that the value of x will be a maximum of 4.

The domain is positive integers less than or equal to 4.

8 0
3 years ago
In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen
Mashcka [7]

Answer:

a) P' = P

   P(t) = 24e^{0.693t} where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

\frac{dP}{dt} = P

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

P(t) = P_0e^{kt}

where P_0 = 24 is the initial population

After 6 month (t = 1), the population is doubled to 48

P(1) = 24e^k = 48

e^k = 2

k = ln(2) = 0.693

Therefore P(t) = 24e^{0.693t}

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

24e^{0.693t} = 1000000

e^{0.693t} = 1000000 / 24 = 41667

0.693t = ln(41667) = 10.64

t = 10.64 / 0.693 = 15.35

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. P' = P_0ke^{kt}

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

24e^{0.5k) = 48

0.5k = ln2 = 0.693

k = 1.386

Therefore, P' = 1.386*24e^{1.386t}

At the mid of the 3rd year, where t = 2.5, we can calculate P'

P' = 1.386*24e^{1.386*2.5} = 1064.67 rabbits/year

4 0
3 years ago
Find x if eg is a median of triangle DEF.. 5x-17 &amp; 3x+1
GREYUIT [131]
If eg is the median, that means
5x-17=3x+12x=18x=9
4 0
3 years ago
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