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Georgia [21]
2 years ago
5

The height H metres of a ball projected upwards t seconds after being projected is given by H=64t - 16t². Find it's initial velo

city​
Mathematics
1 answer:
nordsb [41]2 years ago
4 0

Answer:

initial velocity = 64 m/s

Step-by-step explanation:

Differentiate H = 64t - 16t² to find an equation for velocity:

Velocity = \frac{dH}{dt} = 64 - 32t

Initial velocity (u) is when t = 0:

   u = 64 - 32(0)

⇒ u = 64 - 0

⇒ u = 64 m/s

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Can someone please help me?<br> If g(x) = x2 - 5x + 2, find g(0).
Debora [2.8K]

g(x) = x² - 5x + 2

You are looking for g(0). This means that you must replace all the x values in the equation above with 0

(0)² - 5(0) + 2

Now you need to solve according to the rules of PEMDAS:

(0)² - 5(0) + 2

0 - 5(0) + 2

0 - 0 + 2

0 + 2

2

g(0) = 2

Hope this helped!

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3 years ago
10.56 is greater or 10.65
kiruha [24]
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Solve this Equation 10x+2=32
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3 years ago
In the rectangle below, E1=2x -2, FH=3x+6, and m 4IHG =35°.Find Gl and m LIEH
Tpy6a [65]

Recall that the diagonals of a rectangle bisect each other and are congruent, therefore:

\begin{gathered} FH=2EI, \\ GI=EI. \end{gathered}

Substituting the given expression for each segment in the first equation, we get:

3x+6=2(2x-2).

Solving the above equation for x, we get:

\begin{gathered} 3x+6=4x-4, \\ 3x+6+4=4x, \\ 3x+10=4x, \\ 4x-3x=10, \\ x=10. \end{gathered}

Substituting x=10 in the equation for segment EI, we get:

EI=2*10-2=20-2=18.

Therefore:

GI=18.

Now, to determine the measure of angle IEH, we notice that:

\Delta HFG\cong\Delta GEH,

therefore,

\measuredangle GHF\cong\measuredangle HGE.

Using the facts that the triangles are right triangles and that the interior angles of a triangle add up to 180° we get:

m\measuredangle IEH=90^{\circ}-35^{\circ}=55^{\circ}.

<h2>Answer: </h2>\begin{gathered} m\operatorname{\measuredangle}IEH=55^{\operatorname{\circ}}, \\ GI=18. \\  \end{gathered}

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1 year ago
Please help me with this problem, thank you.
fredd [130]
The answer is 117 degrees
3 0
3 years ago
Read 2 more answers
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