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Georgia [21]
2 years ago
5

The height H metres of a ball projected upwards t seconds after being projected is given by H=64t - 16t². Find it's initial velo

city​
Mathematics
1 answer:
nordsb [41]2 years ago
4 0

Answer:

initial velocity = 64 m/s

Step-by-step explanation:

Differentiate H = 64t - 16t² to find an equation for velocity:

Velocity = \frac{dH}{dt} = 64 - 32t

Initial velocity (u) is when t = 0:

   u = 64 - 32(0)

⇒ u = 64 - 0

⇒ u = 64 m/s

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Lodine-131 is a very useful radioactive isotope that is used to locate and treat cancerous tumors in the body and has a half lif
Dvinal [7]

Using an exponential function, it is found that 4 mg of the substance would still be left after 32 days.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, considering that the initial amount if of 64 mg, and we are working with half-lifes, the equation is given by:

A(t) = 64(0.5)^t

32 days is 32/8 = 4 half-lifes, hence the amount remaining in mg is given by:

A(4) = 64(0.5)^4 = 4

More can be learned about exponential functions at brainly.com/question/25537936

8 0
2 years ago
On an averadge day, a horse might drink 50 L, a sheep might drink 4L,
3241004551 [841]
2610 L of water would be needed every day.
7 0
3 years ago
Can anybody help me with this?
Alexandra [31]
Use your “ H - chart “
3 0
3 years ago
Read 2 more answers
Pls show work/steps for both questions
aleksklad [387]

Answer:

Step-by-step explanation:

\frac{-5+2 \iota}{1+7 \iota}  \times \frac{1-7 \iota}{1-7 \iota} \\=\frac{-5+35 \iota+2 \iota-14 \iota^2}{1-49 \iota^2} \\=\frac{-5+37 \iota-14(-1)}{1-49(-1)} \\=\frac{9+37 \iota}{50} \\=\frac{9}{50} +\frac{37}{50}  \iota

2.

domain is x²≤36

|x|≤6

-6≤x≤6

or [-6,6]

3 0
3 years ago
The vertex of a parabola is (-1.5, -12.5), and its y-intercept is (0, -8).
Ostrovityanka [42]
Y = a(x  + 1.5)^2 - 12.5
y intercept is (0,-8) so:-
-8 = a(0+1.5)^2 - 12.5
-8 = 2.25a - 12.5
a =  4.5/ 2.25 = 2

so we have 

y  = 2 ( x +1.5)^2 - 12.5

solving for x  when y = 0:-
(x + 1.5)^2 = 12.5/2 = 6.25

taking sqrt's  x + 1.5  = +/- 2.5

x =  -4,   1

so the x intercepts are (-4,0) and (1,0)





7 0
4 years ago
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