Answer:
6.25 feet.
Step-by-step explanation:
Let L be the length of the ramp in feet.
We have been given that steel loading ramps are used to load a lawn mower onto a truck bed 37.5 inches above the ground. The ramp make a 30° angle with the ground.
We can see from our attachment that ramp and truck bed forms a right triangle with ground. The truck bed is opposite side and length of ramp is hypotenuse of our given angle.
Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use Sine to solve for L.
Upon substituting our given values in above formula we will get,
Therefore, the length of the ramp is 75 inches.
Let us convert the length of ramp in feet.
1 feet = 12 inches.
Therefore, the length of the ramp is 6.25 feet.
Answer:
the answer is 7 because 7 *7 is 49
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Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
Step-by-step explanation:
Let us consider the general linear equation
Y = MX + C
On a coordinate plane, a line goes through points (0, negative 1) and (2, 0).
Slope = ( 0 - -1)/( 2- 0) = 1/2
When x = 0, Y = -1
Substitutes both into general linear equation
-1 = 1/2(0) + C
C = -1
The equations for the coordinate is therefore
Y = 1/2X - 1
Let's check the equations one after the other
y = negative one-half x minus 1
Y = -1/2X - 1
y = negative one-half x + 1
Y = -1/2X + 1
y = one-half x minus 1
Y = 1/2X - 1
y = one-half x + 1
Y = 1/2X + 1
It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
9514 1404 393
Answer:
a) w(4w-15)
b) w²
c) w(4w -15) = w²
d) w = 5
e) 5 by 5
Step-by-step explanation:
a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.
A = w(4w -15)
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b) If w is the side length, the area of the square is (also) the product of length and width:
A = w²
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c) Equating the expressions for area, we have ...
w(4w -15) = w²
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d) we can subtract the right side to get ...
4w² -15w -w² = 0
3w(w -5) = 0
This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.
The side length of the square is 5 units.
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e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.
The rectangle and square have the same width and the same area, so the rectangle must be a square.
