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2 years ago

8

I need help with this question

2 answers:

yulyashka [42]2 years ago

8 0

Answer:

1/3

Step-by-step explanation:

i hope this helps you! :)

Tomtit [17]2 years ago

4 0

Answer:

1/3

Step-by-step explanation:

When you are subtracting frations with the same denominator, you would only subtract the numerator and keep the denominator the same.

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PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

Charles asked his teammates how many hours they practiced swimming during the week. He recorded his data in the table below and

Kitty [74]

Answer:

The answer is C.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Is the function even or odd?

sweet [91]

Answer:

$f(\theta)=\cos(\theta)$ is an even function.

Step-by-step explanation:

Recall when it means when a function is even or odd. An even function has the following property:

$f(-x)=f(x)$

And an odd function has the following property:

$f(-x)=-f(x)$

So, let's test some values for cos(x).

Let's use π/3:

$f(\pi/3)=\cos(\pi/3)$

From the unit circle, was can see that this is 1/2 (refer to the x-coordinate).

Now, let's find -π/3. This is the same as 5π/3. Thus:

$f(-\pi/3)=\cos(-\pi/3)$

And again from the unit circle, we can see that this is 1/2.

Therefore, despite the negative, the function outputs the same value.

Cosine is an even function.

Notes:

Cosine is an even function and sine is an odd function. It's helpful to remember these as they can help you solve some trig problems!

6 0

2 years ago

Polynormual sum of (x^2+9)+(-3x^2-11x+4)

amid [387]

Answer:

jddxhbjxbjkzkecnd

Step-by-step explanation:

xbsahcbszhjbcjhsbjcvh

5 0

2 years ago

What is the area of the sector? Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter

n200080 [17]

Question:

What is the area of the sector? Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal rounded to the nearest hundredth.

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the values of radius and central angle are not given.

However, I'll answer the question using the attached figure.

From the attached figure, the radius is 3 unit and the central angle is 120 degrees

The area of a sector is calculated as thus;

$Area = \frac{\alpha }{360} * \pi r^2$

Where $\alpha$ represents the central angle and r represents the radius

By substituting $\alpha = 120$ and r = 3

$Area = \frac{\alpha }{360} * \pi r^2$ becomes

$Area = \frac{120}{360} * \pi * 3^2$

$Area = \frac{1}{3} * \pi * 9$

$Area = \pi * 3$

$Area = 3\pi$ square units

Solving further to leave answer as a decimal; we have to substitute 3.14 for $\pi$

So, $Area = 3\pi$ becomes

$Area = 3 * 3.14$

$Area = 9.42$ square units

Hence, the area of the sector in the attached figure is $3\pi$ or 9.42 square units

8 0

2 years ago