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2 years ago

The answer to a system is a(n) A) point B) line C) two points D) equation

Mathematics

2 answers:

mel-nik [20]2 years ago

8 0

I think the answer would be D equation

love history [14]2 years ago

3 0

I think the answer is D ?

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Which equation in slope-intercept form represents a line that is parallel to y=−4x−5 and passes through the point (0,0)?

IrinaK [193]

Answer:

$\displaystyle y = -4x$

Step-by-step explanation:

0 = 0 ± b

$\displaystyle 0 = b \\ \\ y = -4x$

* Parallel Lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so −4 remains the way it is.

I am joyous to assist you anytime.

6 0

2 years ago

How does using a model help me multiply decimals by whole numbers?

valkas [14]

Counting them it simple

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3 years ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
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\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
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\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
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\\y' = \frac{3}{( -32 )}$

7 0

3 years ago

A rectangle is plotted on a coordinate plane. The four vertices are located at (−5,5), (−5,−3), (2,5), and (2,−3). What is the a

n200080 [17]

Answer:

56 square units

Step-by-step explanation:

I'd recomend using something like "Desmos" to plot the points so then you can see the points and the rectangle. Then count the length and width. For the this rectangle the length was 8 and the width was 7, multiply these and you get the answer of 56 sqaure units.

8 0

2 years ago

Help me apappp dkneosk

xenn [34]

Answer:

C: perpendicular lines

Step-by-step explanation:

Download pdf

5 0

3 years ago

Read 2 more answers