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OlgaM077 [116]
2 years ago
7

What is the vertex of y = x2 + 2x +2 O (1,-1) O (2,-2) O (1, 2) 0 (-1, 1)

Mathematics
1 answer:
fredd [130]2 years ago
8 0

Answer:

vertex = (- 1, 1 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = x² + 2x + 2 ← is in standard form

with a = 1 and b = 2 , then

x = - \frac{2}{2} = - 1

substitute x = - 1 into the equation for y- coordinate of vertex

y = (- 1)² + 2(- 1) + 2 = 1 - 2 + 2 = 1

vertex = (- 1, 1 )

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likoan [24]

Answer:

f¯¹(x) = 23/ (6x + 3)

Step-by-step explanation:

f(x) = (23 – 3x)/6x

The inverse, f¯¹, for the above function can be obtained as follow:

f(x) = (23 – 3x)/6x

Let y be equal to f(x)

Therefore, f(x) = (23 – 3x)/6x will be written as:

y = (23 – 3x)/6x

Next, interchange x and y.

This is illustrated below:

y = (23 – 3x)/6x

x = (23 – 3y)/6y

Next, make y the subject of the above expression. This is illustrated below:

x = (23 – 3y)/6y

Cross multiply

6xy = 23 – 3y

Collect like terms

6xy + 3y = 23

Factorise

y(6x + 3) = 23

Divide both side by (6x + 3)

y = 23/ (6x + 3)

Finally, replace y with f¯¹(x)

y = 23/ (6x + 3)

f¯¹(x) = 23/ (6x + 3)

Therefore, the inverse, f¯¹, for the function f(x) = (23 – 3x)/6x is

f¯¹(x) = 23/ (6x + 3)

7 0
2 years ago
25) PLEASE HELP WITH QUESTION, WILL MARK BRAINLIEST + POINTS.
iogann1982 [59]
You take the three zeros and put them back with the x s 

(x-6)(x+5)(x-2)  they are reversed when you put them back in 

multiply the first two and get x^2+5x -6x-30(x-2) 
simplify to x^2-x-30(x-2)

Multiply it out again and get x^3-x^2-30x-2x^2+2x+60
finally simplify and get x^3-3x^2-28x+60 

So the answer is the first one

4 0
3 years ago
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