Answer:
we need more info to answer this question
Answer:
(2.25,-0.5)
Step-by-step explanation:
If you were to graph the equations, they intersect at the points 2.25, and -0.5.
Answer:..............................................................
Answer:
Two buses leave towns 760 mi apart at the same time and travel toward each other. One bus travels
18 mi/h slower than the other. If they meet in
5 hours, what is the rate of each bus?
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Let x be the rate of the slower bus, in miles per hour.
Then the rate of the faster bus is (x+18) mph, according to the condition.
The slower bus covered 5x miles before the buses meet each other.
The faster bus covered 5*(x+18) miles before they meet each other.
The sum of distances covered by buses is 3x + 5*(x+18).
It is equal exactly 760 miles. It gives you an equation
5x + 5(x+18) = 760.
Simplify and solve for x:
5x + 5x + 90 = 760,
10x = 760 - 90,
10x = 670 ====> x = 670%2F10 = 67.
Thus you found the rate of the slower bus. It is 67 miles per hour.
Then the rate of the faster bus is 67 + 18 = 85 mph.
Solved.
Step-by-step explanation:
Hope this helps :D
1. (3,2)....because when finding the slope, we find the the slope of mn and the slope of op are negative reciprocals.
2. y = 5x - 7.....slope here is 5....perpendicular line has a negative reciprocal slope...so the slope has to be -1/5
y= mx + b
slope(m) = -1/5
(-10,3)...x = -10 and y = 3
now we sub and find b, the y int
3 = -1/5(-10) + b
3 = 2 + b
3 - 2= b
1 = b
so ur perpendicular equation is : y = -1/5x + 1